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1 year ago

A value type variable stores a _____. Group of answer choices reference class none of these value expression

Computers and Technology

1 answer:

andrew-mc [135]1 year ago

4 0

In Computer programming, a value type variable can be used to store a: value expression.

<h3>What is a variable?</h3>

A variable can be defined as any name which refers to a location in computer memory that is typically used for storing a value.

<h3>The two types of variable.</h3>

In Computer programming, there are two (2) types of variable and these include:

Reference type variable

Value type variable

Generally, a value type variable can be used to store a <u>value expression</u> or a value of that type.

Read more on variable here: brainly.com/question/20264183

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Compare GBN, SR, and TCP (no delayed ACK). Assume that the timeout values for all three protocols are sufficiently long such tha

kvv77 [185]

Answer and Explanation:

For Go-Back-N:

Host A sent total number of segments is 9.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2,3,4 and 5 because 2nd segment was lost.

Host B sent the number of ACKs are 8.Host B sent ACKs 1 by four times because 2nd segment was lost and sent 4ACKs with sequence numbers 2,3,4 and 5

selective repeat:

Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence numbers 1,3,4,5 and re-sent ACK2 with sequence number 2 because 2nd segment was lost.

TCP :

Host A sent total number of segments is 6.The initial segment numbers are 1,2,3,4,5 and re-sent the segemnts 2 because 2nd segment was lost.

Host B sent the number of ACKs are 5.Host B sent four ACKs with sequence number 2 and There is one ACK with sequence number 6.TCP always send an ACK with expected sequence number

b) If the timeout values for all three protocol are much longer than 5*RTT,then TCP protocol successfully delivers all five data segments in shortest time interval.

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3 years ago

How to use 2 tabs at once on my Lenovo yoga book?

svp [43]

To turn on Multi-window： Method 1: Swipe up from the bottom of Home screen to show Bottom switch, touch Multi-wins. Method 2: Tap Settings on Home screen, tap Multi-window, check Multi-window on the right.

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2 years ago

Dialogue is not a characteristic of functional text because...

kumpel [21]

It is b,<span>dialogue it's speech between characters, and there are no characters and functional text </span>

4 0

3 years ago

You’ve been stuck in bumper-to-bumper traffic for nearly an hour on a hot summer day. The temperature warning light has just com

nekit [7.7K]

Answer:

In a bumper-to-bumper traffic, when the engine starts overheating the situation can be handled by tapping the accelator which will revive the engine.

Explanation:

Overheating of engine can be due to many reasons. But one should know what to do when an engine overheats in a traffic. Bumper-to-bumper traffic is when the cars are so close in traffic that they touch each other. This usually happens when there's a traffic for a long time or on very busy lane. During summer times, it is important to keep checking the engine temperature to avoid any problem.

When one is stuck in bumper-to-bumper traffic with overheating engine, then there are some meausres that one can take. They are:

To put the car on park or neutral mode of driving and tap the accelator which will revive the engine.
The heat can be disperse by rolling down the window and turn the heater up. It will disperse the heat.

6 0

3 years ago

A computer hard disk starts from rest, then speeds up with an angular acceleration of 190 rad/s2 until it reaches its final angu

Nataly_w [17]

The first thing we are going to do is find the equation of motion:
ωf = ωi + αt
θ = ωi*t + 1/2αt^2
Where:
ωf = final angular velocity
ωi = initial angular velocity
α = Angular acceleration
θ = Revolutions.
t = time.
We have then:
ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
ωi = 0
α = 190 rad / s2
Clearing t:
753.60 = 0 + 190*t
t = 753.60 / 190
t = 3.97 s
Then, replacing the time:
θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
θ1 = 1494.51 rad
For (10-3.97) s:
θ2 = ωf * t
θ2 = (753.60 rad / s) * (10-3.97) s
θ2 = 4544,208 rad
Number of final revolutions:
θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
θ1 + θ2 = 961.57 rev
Answer:
the disk has made 961.57 rev 10.0 s after it starts up

3 0

2 years ago

Read 2 more answers