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3 years ago

With solutions of strong acids and strong bases the word strong refers to

Chemistry

1 answer:

Anastaziya [24]3 years ago

5 0

The answer is degree of ionization. I'm guessing you have already taken the quiz.

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How many atoms of aluminum are in 0.1 mol of aluminum?

Gnom [1K]

Answer: The number of 'entities' in a mole of any pure substance is always that. 1 mole is equivalent to the number of atoms in a 12g lump of Carbon12.

Edit: I deliberately avoided using Avogadro's number as that is different, in a technical sense, to a mole. A mole is a base unit of the International System of Units (SI) which recognized amount of substance as an independent dimension of measurement. With this recognition, the Avogadro constant was no longer a pure number but a physical quantity associated with a unit of measurement, the reciprocal mole (mol−1) in SI units.

Therefore Avogadro constant is DERIVED from the mole (nowadays) to give something like 6.02214179 x 10^23 mole^(-1). (based on 2006 evidence)

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3 years ago

Why are group viia elements very active nonmetals

Marina CMI [18]

I’m not sure what you’re asking but- halogens are among the most active nonmetals due to their electron configuration and number of valence electrons.

7 0

3 years ago

Convert 22.4 kg/L to kg/mL

liberstina [14]

1 kg/L -------------- 0.001 kg/mL
22.4 kg/L --------- ??

22.4 x 0.001 / 1 => 0.0224 kg/mL

7 0

4 years ago

A Canadian dime weighs 1.75g and has a thickness of 1.22mm. A Canadian quarter weighs 4.4g and has a thickness of 1.58mm. You ha

balu736 [363]

The mass of the total number of coins is 1405 g.

Since the thickness of each dime is 1.22 mm and we have each pile being 61.0 mm tall, we need to determine the number of dimes in each pile by dividing the height of the pile by the thickness of each dime.

so, number of dimes in each pile = height of each pile/thickness of each dime = 61.0 mm/1.22 mm = 50 dimes.

Since we have 6 piles, the total number of dimes in all the piles is 6 piles × 50 dimes/pile = 300 dimes.

So, there are 300 dimes in the 6 piles.

Since each dime weighs 1.75 g, 300 dimes will weigh 1.75 g/dime × 300 dimes = 525 g.

In the pile of quarters, we have $ 50 worth of quarters.

Since each quarter = $ 0.25, the number of quarters in that pile is total worth of quarter/value of one quarter = $ 50/$ 0.25 = 200 quarters.

Since each quarter weighs 4.4 g, 200 quarters will weigh 4.4 g/quarter × 200 quarters = 880 g

So, the mass of the total number of coins = total mass of dimes + total mass of quarters = 525 g + 880 g = 1405 g

So, the mass of the total number of coins is 1405 g.

Learn more about mass of coin here:

brainly.com/question/19194652

5 0

3 years ago

PLEASE HELP!! WILL MARK BRAINLIEST!! TIME IS RUNNING OUT!!!

Juli2301 [7.4K]

We can use the heat equation,
Q = mcΔT

Where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).

According to the given data,

Q = 300 J

m = 267 g

c = ?
ΔT = 12 °C

By applying the formula,

300 J = 267 g x c x 12 °C
c = 0.0936 J g⁻¹ °C⁻¹

Hence, specific heat of the given substance is 0.0936 J g⁻¹ °C⁻¹.

6 0

4 years ago