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Alexus [3.1K]
2 years ago
11

Based on the equation, how many grams of Br2 are required to react completely with 72.4 grams of AlCl3

Chemistry
1 answer:
svlad2 [7]2 years ago
5 0

Answer:  131 g of bromine is required.

Explanation:

The balanced equation will be :

2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of AlCl_3

\text{Number of moles}=\frac{72.4g}{133g/mol}=0.544moles

According to stoichiometry :

2 moles of AlCl_3 require  = 3 moles of Br_2

Thus 0.544 moles of AlCl_3 require=\frac{3}{2}\times 0.544=0.816moles  of Br_2

Mass of Br_2=moles\times {\text {Molar mass}}=0.816moles\times 160g/mol=131g

Thus 131 g of bromine is required.

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Hope this helps you buddy!!

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