Answer:
Weight of the dog on surface of earth is 140.14 Newton.
Given:
mass of the dog = 14.3 kg
To find:
Weight of the dog = ?
Formula used:
Weight of the dog is given by,
W = mg
Where, W = weight of the dog
m = mass of the dog
g = acceleration due to gravity
Solution:
Weight of the dog is given by,
W = mg
Where, W = weight of the dog
m = mass of the dog = 14.3 kg
g = acceleration due to gravity
W = 14.3 × 9.8
W = 140.14 Newton
Weight of the dog on surface of earth is 140.14 Newton.
Answer:
1.74x10⁻⁵ V
Explanation:
n = 85.7 turns/cm => 8570 turns/metre
The field inside the long solenoid is given by B = μ₀ni
B = 4πx10⁻⁷ x 8570 x 0.175t² = 1.884x10⁻³ t²
dB/dt = 3.78x10⁻³ t
Cross-sectional Area'A'= 2.16 cm²=> 2.16 x
m²
Now, rate of change of flux linkage '|Emf|' is given by:
|Emf| = d(NAB)/dt = NA dB/dt
|Emf| = 5 x 2.16 x
x 3.78x10⁻³ t
|Emf| = 4.0824x10⁻⁶ t
Considering time 't' at which the current = 3.2A
, we have
3.2 = 0.175T²
T²
= 3.2/0.175
T = 4.28 s
|emf| = 4.0824x10⁻⁶ t => 4.0824x10⁻⁶ x4.28
|emf|= 1.74x10⁻⁵ V
Therefore,the magnitude of the emf induced in the secondary winding is 1.74x10⁻⁵ V
Answer:
1.33 cm
Explanation:
L = 32 m, T 1 = 0 degree C , T2 = 32 degree C
Thermal expansion coefficient of steel, α = 13 x 106-6 per degree C
Let ΔL be the increase in length.
ΔL = L x α x ΔT
ΔL = 32 x 13 x 10^-6 (32 - 0)
ΔL = 0.0133 m = 1.33 cm
Answer:
Total energy produced 19135.362 MJ/year
Explanation:
given details:
total energy produced = 2090 Btu per hour
1 Btu = 1.055kJ
Total energy produced per year in mega joule is = 2090*1.055 *365*24
= 19315362 KJ/year
In mega joule per year 
mega joule per year = 19135.362 MJ/year