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KiRa [710]
3 years ago
12

The MSDS for glacial acetic acid says that it is a flammable liquid that can severely burn any human tissue it comes in contact

with. It reacts with bases, various metals, and strong oxidizing agents. Its vapors can form explosive mixtures with air. Based on this information, which statement is applicable to glacial acetic acid?
Physics
1 answer:
Alex777 [14]3 years ago
3 0

Answer: D) It should be handled in a fume hood, away from open flames.

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A hockey puck slides 55.0 m along the length of the rink in just 1.25 s. The slight friction between the puck and the ice provid
topjm [15]

Answer:

44.8 m/s

Explanation:

Use the Initial Speed Formula:

InS = 2(d/t) - Final Speed

InS = 2(55/1,25) - 43.2

InS = 2.44 - 43,2

InS = 88 - 43,2

InS = 44.8 m/s

3 0
2 years ago
You are designing an optical fiber scope for directing light into a confined area. You want to keep light within the fiber. Base
shepuryov [24]

Answer:

Explanation:

 For entry of light into tube of unknown refractive index

sin ( 90 - 25 ) / sinr = μ , μ is the refractive index of the tube , r is angle of refraction in the medium of tube

r = 90 - C where C is critical angle between μ and body medium in which tube will be inserted.

sin ( 90 - 25 ) / sin( 90 - C)  = μ

sin65 / cos C = μ

sinC = 1.33 / μ  , where 1.33 is the refractive index of body liquid.

From these equations

sin65 / cos C = 1.33 / sinC

TanC = 1.33 / sin65

TanC = 1.33 / .9063

TanC = 1.4675

C= 56°

sinC = 1.33 / μ

μ = 1.33 / sinC

= 1.33 / sin56

= 1.33 / .829

μ = 1.6   Ans

3 0
2 years ago
A spring stretches 3.5 cm when a 9 g object is hung from it. The object is replaced with a block of mass 26 g which oscillates i
evablogger [386]

Answer:

The period of motion  of new mass T = 0.637 sec

Explanation:

Given data

Mass of object (m) = 9 gm = 0.009 kg

Δx = 3.5 cm = 0.035 m

We know that spring force is given by

F = m g

F = 0.009 × 9.81 = 0.08829 N

Spring constant

k = \frac{F}{x}

k = \frac{0.08829}{0.035}

k = 2.522 \frac{N}{m}

New mass(m_1) = 26 gm = 0.026 kg

Now the period of motion is given by

T = 2 \pi \sqrt{\frac{m}{k} }

T = 2 \pi \sqrt{\frac{0.026}{2.522} }

T = 0.637 sec

This is the period of motion  of new mass.

3 0
2 years ago
For a 50 kV anode voltage, what is the maximum photon energy of the x-ray radiation?
V125BC [204]

Answer:

The energy of photon, E=8\times 10^{-15}\ J

Explanation:

It is given that,

Voltage of anode, V=50\ kV=50\times 10^3\ V=5\times 10^4\ V

We need to find the maximum energy of the photon of the x- ray radiation. The energy required to raise an electron through one volt is called electron volt.

E=eV

e is charge of electron

E=1.6\times 10^{-19}\times 5\times 10^4

E=8\times 10^{-15}\ J

So, the maximum energy of the x- ray radiation is 8\times 10^{-15}\ J. Hence, this is the required solution.

6 0
3 years ago
A man paddles a canoe at 6 km per hour. If he paddles on a river with a current of 6 km per hour, what is the speed of the canoe
Romashka-Z-Leto [24]

Answer:

If the canoe heads upstream the speed is zero. And directly across the river is  8.48 [km/h] towards southeast

Explanation:

When the canoe moves upstream, it is moving in the opposite direction of the normal river current. Since the velocities are vector (magnitude and direction) we can sum each vector:

Vr = velocity of the river = 6[km/h}

Vc = velocity of the canoe = -6 [km/h]

We take the direction of the river as positive, therefore other velocity in the opposite direction will be negative.

Vt = Vr + Vc = 6 - 6 = 0 [km/h]

For the second question, we need to make a sketch of the canoe and we are watching this movement at a high elevation. So let's say that the canoe is located in point 0 where it is located one of the river's borders.

So we are having one movement to the right (x-direction). And the movement of the river to the south ( - y-direction).

Since the velocities are vector we can sum each vector, so using the Pythagoras theorem we have:

Vt = \sqrt{(6)^{2} +(-6)^{2} } \\Vt=8.48[km/h]

5 0
3 years ago
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