Among those two medium, light would travel faster in the one with a reflection angle of (when light enters from the air.)
Explanation:
Let denote the speed of light in the first medium. Let denote the speed of light in the air. Assume that the light entered the boundary at an angle of to the normal and exited with an angle of . By Snell's Law, the sine of and would be proportional to the speed of light in the corresponding medium. In other words:
.
When light enters a boundary at the critical angle , total internal reflection would happen. It would appear as if the angle of refraction is now . (in this case, .)
Substitute this value into the Snell's Law equation:
.
Rearrange to obtain an expression for the speed of light in the first medium:
.
The speed of light in a medium (with the speed of light slower than that in the air) would be proportional to the critical angle at the boundary between this medium and the air.
For , is monotonically increasing with respect to . In other words, for in that range, the value of increases as the value of increases.
Therefore, compared to the medium in this question with , the medium with the larger critical angle would have a larger . such that light would travel faster in that medium.
Answer D In alkali earth metals reacrivity increases from top to bottom (opposite of b) This is because as you go down, the electron shells increase by 1 shell. The farther away a shell is from the nucleus, the higher its tendency to react. D is true because the more reactive an alkali metal is, the more vigorous the reaction will be with water.
You can use the displacement method or the eureka can so basically in the displacement can what you have to do is to put some water into a measuring cylinder and measure its volume before adding the irregular shaped object and then measuring the level of water which had been displaced and then eureka can you can check online