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kumpel [21]
3 years ago
15

I need helppppppppop​

Mathematics
1 answer:
klemol [59]3 years ago
7 0

Step-by-step explanation:

(a)

2 \frac{1}{2}\div \frac{5}{2}=\dfrac{\frac{2\times2+1}{2}}{\frac{5}{2}}\\\Rightrrow\dfrac{\frac{5}{2}}{\frac{5}{2}}=1

(b)

3\div \frac{2}{3}=\dfrac{3}{\frac{2}{3}}=\frac{3\times3}{2}=\frac{9}{2}

(c)

6 \frac{3}{4}\div 2\frac{1}{4}=\dfrac{\frac{6\times4+3}{4}}{\frac{2\times4+1}{4}}\\\Rightarrow \dfrac{\frac{27}{4}}{\frac{9}{4}}=\frac{27}{9}=3

(d)

\frac{1}{3}\div 3=\dfrac{\frac{1}{3}}{3}=\frac{1}{9}

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1. Number 1 and 2 and 4 is a function, 2. number 1 is a function

Step-by-step explanation:

1)To know if it's a function or not run vertical lines through multiple places of the graph. If it is a function every single time you do the vertical line test it should only go over the line once. If you do the vertical line test on 3 you will see that it went over the line on the graph, so we know not a function. Graphs 1, 2, and 4m however, are different, when you do the vertical line test on those graphs it only goes over them once.

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