Prime factorisation of 8232
2 answers:
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You can get this by using the quadratic equation with a = 7, b = -1, c = -9
Answer:
\frac{x^4+5}{x^3(x^2+6)} =\frac{A}{x}+\frac{B}{x^2}+\frac{D}{x^3} +\frac{Ex+F}{x^2+6}
Step-by-step explanation:
Answer:
Step-by-step explanation:
Factor theorem : If x=a is a zero of a polynomial p(x) then (x-a) is a factor of p(x).
Given: Zeroes of polynomial : -4,0, 1, and 4.
Then Factors = [By factor theorem ]
Multiplying these factors to get polynomial in standard form.
Hence, B is the correct option.