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3 years ago

What is a decay series?

Chemistry

2 answers:

nikitadnepr [17]3 years ago

8 0

Answer:

Explanation:

took test Edg

Ulleksa [173]3 years ago

5 0

Answer:

a chain of decays that result in a stable nucleus

Explanation:

Decay series is a series of decay in which radioactive element is decomposed in different elements until it produces one stable atom.

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When dinitrogen pentaoxide, a white solid, is heated, it decomposes to produce nitrogen dioxide gas and

AysviL [449]

9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

Oxygen produced - 1.618 gram

Decomposition of $N_2O_5$ takes place.

Find - Amount of $NO_2$ produced.

The decomposition reaction is as follows -

$2N_2O_5$ --> $4NO_2 + O_2$

Moles of $O_2$ gas = $\frac{1.6}{16}$ =0.1 moles.

1 mole of $O_2$ is produced from 2 moles of dinitrogen pentoxide

0.1 mole of $O_2$ will be produced from = 0.2 moles.

Now, 2 moles of dinitrogen pentoxide produce 4 moles of $NO_2$

$NO_2$ produced will be - 0.4 moles.

Weight of $NO_2$ produced - 0.4 X 46

Weight of $NO_2$ produced - 18.4 gram

Thus, grams of $NO_2$ produced are 18.4

Now calculate the volume of $NO_2$

Given data are:

P=103.25 kPa =1.01899827 atm

T= 22.75 °C +273 = 295.75 K

n=0.4 moles

V=?

R= 0.0821 liter·atm/mol·K

Putting the value in PV=nRT

V = $\frac{nRT}{P}$

V = $\frac{0.4 \;moles \;X \;0.0821\; liter\;atm/\;mol \;K X \;295.75 \;K}{1.01899827 atm}$

V= 9.5314 L

Hence, 9.5314 L is the volume of nitrogen dioxide formed at 103.25 kPa and 22.75 °C.

Learn more about the ideal gas equation here:

brainly.com/question/13450124

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8 0

2 years ago

What is the density of an object with a volume of 11.24 L and a mass of 3.45 g ?

Tasya [4]

Answer:

0.306 g/L

Explanation:

D = M/V

D= 3.45 g/11.24 L

D= 0.306 g/L

5 0

3 years ago

You test the pH of the kiddie pools water. You discover thats its pH is 6.3. Is the water too acidic or too basic? how could thi

Luda [366]

Having a pH of 6.3 for a kiddie pool would be considered as acidic. You need to increase this value to keep it safe for use. The safest pH level would be from 7.2 to 7.4. This would be safe for the skin of the one who uses the pool. Hope this answers the question.

3 0

3 years ago

Read 2 more answers

What are the empirical formula and empirical formula mass for N2S3

ASHA 777 [7]

What are the options the your question

3 0

4 years ago

Combustion of 25.0 g of a hydrocarbon produces 86.5 g of co2. what is the empirical formula of the compound?

Step2247 [10]

Combustion is a reaction between a combustible substance and oxygen, to ultimately produce carbon dioxide and water. Reaction between carbon and oxygen would give,

C + O2 ------> CO2

Here, we have 86.5 grams of carbon dioxide, CO2, which is a product of combustion. Dividing this mass by the molar mass of CO2, which is 44 grams, we can determine the number of moles of CO2.

 86.5 g CO = 1.966 moles CO2
44 g CO2/ mole

Considering that CO2 is composed of 1 mole of carbon and 2 moles of oxygen, and that with complete combustion, 1 mole of carbon reacts to produces 1 mole of CO2, we can then determine the mass of the carbon in the hydrocarbon fuel.

1.966 moles CO2 x 1 mole C x 12 g C = 23.59 g C
1 mole CO2 1 mole C

We were given 25.0 grams of the fuel hydrocarbon. A hydrocarbon is a substance consisting of carbon and hydrogen. To determine the mass of the hydrogen in the fuel, we simply subtract 23.59 grams from 25.0 grams.

25.0 g - 23.59 g = 1.41 grams Hydrogen

To know the number of moles of hydrogen, we divide the mass of the hydrogen in the fuel by the molar mass of hydrogen, which is 1.01 g/mole. Thus, we have 1.396 mole hydrogen.

To determine the empirical formula, we divide the number of moles carbon by the number of moles hydrogen, and find a factor that would give whole number ratios for the carbon and hydrogen in the fuel,

Carbon: 1.966 mol = 1.408 x 5 (factor) = 7
1.396 mol

Hydrogen: 1.396 mol = 1.00 x 5 (factor) = 5
1.396 mol

Thus, the empirical formula is C7H5

4 0

4 years ago

Read 2 more answers