What are the empirical formula and empirical formula mass for N2S3

Which of the following is a way that materials are used?

Svetach [21]

Answer:

the answer is B.Construction

Explanation:

8 0

3 years ago

PLEASE HELP: Which is the state change that occurs when a solid becomes a gas without becoming a liquid first?

nekit [7.7K]

It is called sublimation

4 0

3 years ago

An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.

____ [38]

Answer:

(a) Density of the air = 1.204 kg/m3

(b) Pressure = 93772 Pa or 0.703 mmHg

(c) Force needed to open the door = 15106 N

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

$\rho_{air}=\frac{P}{R*T}$

First, we change the units of P to Pa and T to deg K:

$P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K$

Then we have

$\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}$

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

$PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg$

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

$F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N$

7 0

3 years ago

Suppose there is 1. 00 l of an aqueous buffer containing 60. 0 mmol of acetic acid (pa=4. 76) and 40. 0 mmol of acetate. Calcula

8_murik_8 [283]

For 1. 00 l of an aqueous buffer containing 60. 0 mmol of acetic acid (pa=4. 76) and 40. 0 mmol of acetate, the pH of this buffer is 4.58.

<h3>What is handerson Hasselbalch equation? </h3>

It is expressed as:

pH = pKa + log [A-]/[HA]

where,

[A-] is the molar concentration of conjugate base

[HA] is the molar concentration of weak acid

Given,

pKa = 4.76

<h3>Calculation of concentration:</h3>

For acetic acid

C = n/V

= 60/1000

= 0.06M

For acetate

C = 40/1000

= 0.04M

Now, substituting values in equation we get,

pH = 4.76 + log(0.04/0.06)

pH = 4.76 + (-0.176)

pH = 4.58

Thus by using Henderson Hasselbalch equation we find the value of pH of the buffer is 4.58.

learn more about pH :

brainly.com/question/9529394

#SPJ4

6 0

1 year ago

A certain compound of bromine and fluorine is used to make UF6, which is an important chemical in the processing and reprocessin

Aleksandr [31]

Answer: The empirical formula is $BrF_3$

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Br= 58.37 g

Mass of F = (100-58.37) = 41.63 g

Step 1 : convert given masses into moles.

Moles of Br= $\frac{\text{ given mass of Br}}{\text{ molar mass of Br}}= \frac{58.37g}{80g/mole}=0.73moles$

Moles of F = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{41.63g}{19g/mole}=2.2moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Br = $\frac{0.73}{0.73}=1$

For F = $\frac{2.2}{0.7}=3$

The ratio of Br: F= 1 : 3

Hence the empirical formula is $BrF_3$

8 0

3 years ago