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Anna007 [38]
4 years ago
11

Okay so i dont understand so please help me if you do

Mathematics
1 answer:
larisa [96]4 years ago
5 0

Answer:

C. (-x, y)

Step-by-step explanation:

If you look at the graph the rectangle with the D', E', F', and G'. This is the one we are looking at.

It was rotated on the y-axis. and it stayed in the positive y.

It went to the negative x though.

C. (-x, y) is your answer.

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Pls help with this math question
sergij07 [2.7K]

Answer:

no

Step-by-step explanation:

because for it to be a function it needs to be negative

8 0
3 years ago
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A survey is targeted at 12 year old children. Which questions are appropriate for the population? Choose all that apply.
zubka84 [21]

Answer:

options number four is correct because they are children and they can able to identify the book.

3 0
4 years ago
If thewronskian w of f and g is 3e4t,and if f(t) = e2t,find g(t).
ehidna [41]
W(f(x),g(x))=\begin{vmatrix}f(x)&g(x)\\f'(x)&g'(x)\end{vmatrix}=f(x)g'(x)-g(x)f'(x)

We have f(t)=e^{2t}\implies f'(t)=2e^{2t}, so

W(f(t),g(t))=e^{2t}g'(t)-2e^{2t}g(t)=3e^{4t}
\implies e^{-2t}g'(t)-2e^{-2t}g(t)=3
\implies\dfrac{\mathrm d}{\mathrm dt}[e^{-2t}g(t)]=3
\implies e^{-2t}g(t)=\displaystyle\int3\,\mathrm dt
\implies e^{-2t}g(t)=3t+C
\implies g(t)=3te^{2t}+Ce^{2t}

where C is any arbitrary constant.
8 0
4 years ago
Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 2, and the given zeros. -
Musya8 [376]

Answer:

A least degree polynomial, having rational coefficients and a leading coefficient of 2, with,-4, 0, 2, and 4 as the zeros of the polynomial is;

f(x) = 2·x⁴ - 4·x³ - 32·x² + 64·x

Step-by-step explanation:

The given parameters of the polynomial are;

The leading coefficient of the polynomial = 2

The zeros of the polynomial = -4, 0, 2, 4

We note that zeros of -4, and 4 gives a factor of the form, (x² - 4²)

For a zero of the polynomial equal to 0, one of the factors of the polynomial is equal to 'x'

To have a leading coefficient of 2, we can add '2' as a factor of the polynomial

Therefore, we can have the factors of the polynomial as follows;

(x² - 4²)·2·x×(x - 2) = 0

From the above equation, using a graphing calculator, we get the following possible polynomial;

(x² - 4²)·2·x×(x - 2) = 2·x⁴ - 4·x³ - 32·x² + 64·x = 0

Therefore, a polynomial, function of least degree that has rational coefficients, a leading coefficient of 2,and the zeros, -4, 0, 2, and 4 is  f(x) = 2·x⁴ - 4·x³ - 32·x² + 64·x.

4 0
3 years ago
A regular number cube is rolled. What is the probability that a 3 will not be rolled?
Elena-2011 [213]

Answer:

5/6

Step-by-step explanation:

3 0
2 years ago
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