How do you find the circumference and pie of a circle? Please help me I want to know. Please and thank you.

a 5 sided solid has the numbers 1,2,3,4, and 5. what is the probability of rolling two five-sided solids and getting a sum of ei

kipiarov [429]

So this is going to be alot of writing to show my thinking but ill bold the answer.

1,1
1,2
1,3
1,4
1,5

2,1
2,2
2,3
2,4
2,5

3,1
3,2
3,3
3,4
3,5

4,1
4,2
4,3
4,4
4,5

5,1
5,2
5,3
5,4
5,5

next ill mark all the ones that equal 4 or 8 when added together, with an x

1,1
1,2
x1,3
1,4
1,5

2,1
x2,2
2,3
2,4
2,5

x3,1
3,2
3,3
3,4
x3,5

4,1
4,2
4,3
x4,4
4,5

5,1
5,2
x5,3
5,4
5,5

that is 6 (that equal 4 or 8) out of 25

so your ratio would be 6:19

6 0

3 years ago

The figure shows a cylinder of diameter 12cm and height = 15cm. A hole in the shape of cone is bored into one of its end. If the

Lisa [10]

Answer:

$\bold{495\pi} \approx \bold{1555.088 cm^3}$

Step-by-step explanation:

There was no figure but the question is clear

Volume of a cylinder is given by the formula $\bold{\pi r^2h}\\$

where r is radius of base of cylinder, h is the height

Volume of a cone is given by $\bold{\frac{1}{3} \pi r^2 h}$

where r is the radius of base of cone, h is the height

The radius of the cylinder = $\frac{1}{2}$ (diameter) = $\frac{1}{2}$ (12) = 6cm

Height of cylinder = 15cm

Volume of cylinder $V_{cyl} = \pi (6)^2 15 = \pi (36)15 = \bold{540\pi}$

Radius of cone = $\frac{1}{2}$ (radius of cylinder) = $\frac{1}{2}$ (6) = 3 cm

Height of cone same as height of cylinder = 15cm

Volume of cone, $V_{cone} = \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (3)^2 15 = \frac{1}{3}(9)15\pi = \bold{45\pi}\\$

Difference is the volume of the remaining solid

$V_{cyl} - V_{cone} = 540\pi - 45\pi = \bold{495\pi} \approx \bold{1555.088 cm^3}$

5 0

2 years ago

Which number is prime... 11. 49. 51. 81

Rzqust [24]

The answer to your question is 11

8 0

4 years ago

Can someone solve this question

pogonyaev

(g/f)(x)= g(x)/f(x) =

= (x² - 6) /(3x +1)

3x+1≠0

3x≠-1

x≠ - 1/3

(g/f)(x)= (x² - 6) /(3x +1), when x≠ - 1/3

Answer: A.

6 0

3 years ago

In 1975 1000 tons of coal was manufactured. It is 10% greater in 1976 and 5% less in 77. What is the final about of coal in 1977

Digiron [165]

In 1975 it was 1000tons, ok, well, in 1976 it went up by 10%, how much is a 10% increase?

$\bf \begin{array}{ccllll}
coal&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1000&100\\
x&100+10
\end{array}\implies \cfrac{1000}{x}=\cfrac{100}{100+10}\implies \cfrac{1000\cdot 110}{100}=x
\\\\\\
1100=x$

well, in 1976 it was 1100 tons then, and in 1977 it went down by 5% of 1100, well, if we take 1100 to be the 100%, then what is a 5% decrease?

$\bf \begin{array}{ccllll}
coal&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1100&100\\
x&100-5
\end{array}\implies \cfrac{1100}{x}=\cfrac{100}{100-5}\implies \cfrac{1100\cdot 95}{100}=x$

5 0

3 years ago