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Free_Kalibri [48]

4 years ago

10

A candle crafter packs 180 candles in 5 boxes. Each box holds the same number of candles. Which equation shows the relationship

between the number of boxes, b, and the number of candles, n?

1 answer:

Evgen [1.6K]4 years ago

8 0

I think the answer is 900

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Please Help! Will give BRAINLIEST! I don't know how to do this.

OverLord2011 [107]

Therefore x intercept(a) is <span>3 </span> and y intercept(b) is 3<span> </span>.

5 0

3 years ago

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The area of two similar triangles are 50dm^2 and 32dm^2. The sum of their perimeters is 117dm. What us the perimeters of each of

Kay [80]

Answer:

Perimeter of one triangle is 65 dm

Perimeter of other triangle is 52 dm

Step-by-step explanation:

Please remember the concept

If sides are in the ratio of a:b

Then the area in the ratio of $a^{2} :b^{2}$

It is given sum of their perimeter is 117.

Let the small triangle has perimeter as x.

So, perimeter of big triangle is 117-x.

So, we can set up equation as

$\frac{50}{32} =\frac{x^{2} }{(117-x)^{2} }$

Cross multiply

50(117-x)^2 =32x^2

Expand the left side

50 $(13689 -234x+x^{2} )$ = $32x^{2}$

Distribute the left side

684450-11700x+ $50x^{2}$ = $32x^{2}$

Subtract both sides $32x^{2}$ and rewrite it $18x^{2} -11700x+684450=0$

Solve this quadratic for x.

Divide both sides of the equation by 18 to simplify.

$x^{2}$ -650 x+38025=0

Now, if possible let's factor

Find two integers whose multiplication is 38025 but adds to -650.

-65 and -585 works.

So, we can rewrite it as

(x -65)(x-585) =0

Solve them using zero product property

x=65, x=585

So, x=65 works here.

So, perimeter of one triangle is 65 dm

Perimeter of other triangle is 117-65= 52 dm

5 0

3 years ago

Can any one please do this for me I did not know how to do it can some one please help me

CaHeK987 [17]

Answer:

Length ≈ 31cm

Width ≈ 10cm

Step-by-step explanation:

$Let -the-length-be : x\\Let-the-width-be :y\\\\According- to- the- question ; \\x = 3(y)\\x=3y ---------(1)\\2(l+w)=82\\2(x+y)=82\\2x+2y =82 --------(2)\\Substitute- the - given- value- for ; x -in - equation---(1) into -equation (2)\\2(3y)+2y =82\\6y+2y=82\\8y =82\\\frac{8y}{8} =\frac{82}{8} \\y = 10.25\\\\Substitute 10.25 -for ;y -in -eq 1\\x=3y ---------(1)\\x = 3(10.25)\\x = 30.75$

CHECK

$Length =31\\Width = 10\\P = ?\\P= 2(l+w)\\P = 2(31+10)\\P = 2(41)\\P= 82cm$

3 0

3 years ago

Use a number line to approximate the value of root 33

dsp73

Let's think about the square root of 33 here for a second.

What two perfect squares surround 33?

The answer is 25 and 36.

Then, let's take the square root of both 25 and 36, which are 5 and 6. Therefore, since the square root of 25 and 36 are both nearest to the square root of 33, then the square root of 3 must be between 5 and 6.

The correct answer is A (or option 1): 5 < root 33 < 6

Hope this helps! :)

5 0

3 years ago

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A polygon with 12 sides is called a/an <br> a. dodecagon. <br> b. pentagon. <br> c. undecagon.

Pepsi [2]

The answer is A. dodecagon.

5 0

3 years ago

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