Answer:
r = 23
Step-by-step explanation:
m = (y2 - y1)/(x2 - x1)
5 = (3 - r)/(-8 - (-4))
5 = (3 - r)/(-8 + 4)
3 - r = 5 × -4
3 - r = -20
-r = -23
r = 23
Answer:
798.15
Step-by-step explanation:
heres a neat trick you can do instead of doing that long process to get 15% of 5321 just use a calculator and do 5321 x .15
Answer:
A.) Max at x = 6 and Min at x = -6
Step-by-step explanation:
We say that f(x) has a relative (or local) maximum at x=c if f(x)≤f(c) f ( x ) ≤ f ( c ) for every x in some open interval around x=c . We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on.
Answer:
#carry on learning
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
