Please help! Correct answer will get brainliest! Gabe amodeo a nuclear physicist needs 30 liters of a 40 percent acid solution.
He currently has a thirty percent solution and 60 percent solution. How many liters of each does he need to make the needed 30 liters of 40% alcohol solution?
Given 30% and 60% to make 40% solution. The ratio of vol (30%) : vol (60%) solution is given by (60-40) : (40-30) =2:1 So he will need 30*(2/(2+1))=20 L of 30% solution, and 30*(1/(2+1))=10 L of 60% solution.
Solving by algebra: Let x=volume of 30% solution, then (30/100)x+(60/100)(30-x) = (40/100)*30 Expand and solve for x 0.3x+0.6(30-x) = 0.4*30 18-12=(0.6-0.3)x x=6/0.3=20 L (30% solution) (30-x)=30-20=10 L (60% solution)
