U(x)= x^2+1<br> w(x)= √x+6<br><br> Find the following.<br> (u o w) (3)=__<br> (w o u) (3)=_

Suppose we take two different random samples from the same population of test scores. The population mean and standard deviation

denis23 [38]

Answer:

The correct option is (i) I expect the confidence interval based on the sample of 64 data values to be more precise.

Step-by-step explanation:

Consider the provided information.

The sample size is inversely proportional to the standard error of the sample mean decreases. $\sigma_M=\frac{\sigma}{N}$

As the size increase the standard error of the sample mean decreases.

Hence, for greater precision select the confidence interval based on the greater sample of data.

Therefore, we expect the confidence interval based on the sample of 64 data values to be more precise.

The correct option is (i) I expect the confidence interval based on the sample of 64 data values to be more precise.

6 0

3 years ago

If X=20°, Y=135°, what will Z be

Veronika [31]

The value of Z would be 225°

<h3>What is the angle at a point?</h3>

The angle at a point are angles that add up to 360°

Thus, X + Y + Z = 360°

X = 20°

Y = 135°

Then, Z = 360° - X - Y

Z = 360° - 20° + 135°

Z = 360° - 155°

Z = 205°

Therefore, the value of Z is 205°

Learn more about angle at a point here:

brainly.com/question/24839702

#SPJ1

6 0

2 years ago

The coordinates of the vertices of triangle ABC are A(3,6), B(6, 3), and C(9, 9). If triangle ABC Is dilated by 1/3x and 1/3y to

katovenus [111]

Answer:

$A' = (1,2)$

$B'=(2,1)$

$C' =(3,3)$

Step-by-step explanation:

Given

$A = (3,6)$

$B = (6,3)$

$C = (9,9)$

$Scale = \frac{1}{3}$

Required

Determine the vertices of ABC

If truly the question asks for the vertices of ABC, then the vertices are:

$A = (3,6)$ $B = (6,3)$ $C = (9,9)$

However, I'm quite sure that's not the requirement of the question. So, I'll solve for A'B'C'

To do this, we simply multiply the vertices of ABC by the scale of dilation.

$(A'B'C') = Scale\ Factor * (ABC)$

$A' = \frac{1}{3} * A$

$A' = \frac{1}{3} * (3,6)$

$A' = (\frac{3}{3},\frac{6}{3})$

$A' = (1,2)$

$B' = \frac{1}{3} * B$

$B' = \frac{1}{3} * (6,3)$

$B' = (\frac{6}{3},\frac{3}{3})$

$B'=(2,1)$

$C' = \frac{1}{3} * C$

$C' = \frac{1}{3} * (9,9)$

$C' = (\frac{9}{3},\frac{9}{3})$

$C' =(3,3)$

6 0

3 years ago

Find tan angle c<br> A.5/13<br> B. 12/23<br> C. 12/5<br> D. 13/5

NikAS [45]

Answer:

It's 12/5 . When u divide the BC by AB ie. tanC becomes 12/5 .......Try it hope it helps!

8 0

3 years ago

Read 2 more answers

G(x)=2x-x3+8 polynomial function

KonstantinChe [14]

the answer is 8 G(×) =0 interpret something like that but yeah

4 0

3 years ago

U(x)= x^2+1 w(x)= √x+6 Find the following. (u o w) (3)=__ (w o u) (3)=__

U(x)= x^2+1 w(x)= √x+6 Find the following. (u o w) (3)= (w o u) (3)=