Let us set up some variables:
Now let us set up some equations based on the facts:
- length of rectangle is 4 times its width --> L = 4W
- perimeter of rectangle is 80 --> 2L + 2W = 80
Equations:
L = 4W -- equation 1
2L + 2W = 80 -- equation 2
Plug the value of L from equation 1 into equation 2
2(4W) + 2W = 80
8W + 2W = 80
10W = 80
W = 8 -- equation 3
Plug the value of W from equation 3 into equation 1:
L = 4W = 4 * 8 = 32
Therefore the length is 32 and the width is 8.
Hope that helps!
The formula to find the volume is 1/2(l*w*h)
Height= 7.6
Width=9
Length=13
So, 1/2(7.6*9*13) and you will get the answer
2-5/q=16
-5/q =2=16
(-5)+qx2/q=16
q=-5/14
Answer: (B) 30 gallons.
Step-by-step explanation: Lets subtract 110 - 78 to find the maximum amount of additional water, w that can be added to the tub.
110 - 78 = 32.
round 32 to 30.
So, a reasonable value would be 30 gallons.
