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Paul [167]
3 years ago
6

A ∠A and ∠ B ∠B are supplementary angles. If m ∠ A = ( 8 x + 6 ) ∘ ∠A=(8x+6) ∘ and m ∠ B = ( 7 x + 24 ) ∘ ∠B=(7x+24) ∘ , then fi

nd the measure of ∠ B ∠B.

Mathematics
1 answer:
kolbaska11 [484]3 years ago
5 0

Answer:

< B = 94

Step-by-step explanation:

Remark

You should edit the question. The way you wrote it, , it looks like you have to square two binomials. That isn't the way it is given I don't think. You are told that A and B are supplementary. That means

A+B = 180

Equation

(8x + 6) + (7x + 24) = 180          Remove the brackets

Solution

8x + 6 + 7x + 24 = 180              Collect like terms

15x + 30 = 180                           Subtract 30 from both sides

15x = 180 - 30

15x = 150                                   Divide by 15

x = 150 / 15

x = 10

Answer

What you need is <B

<B = 7x + 24

<B = 7*10 + 24

<B = 70 + 24

<B = 94

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Which is the equation of a line that passes through (1,8) and (6,4)
Sati [7]

Answer:

<em>y = - </em>\frac{4}{5}<em> x + </em>\frac{44}{5}<em> </em>

Step-by-step explanation:

(6, 4)

(1, 8)

m = \frac{8-4}{1-6} = - \frac{4}{5}

y - 4 = - \frac{4}{5} ( x - 6 )

<em>y = - </em>\frac{4}{5}<em> x + </em>\frac{44}{5} ⇔ y = - 0.8x + 8.8

8 0
3 years ago
On Sunday, Sheldon bought 4 1/2 kg of plant food. He used 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plant
VladimirAG [237]

Answer:

a) 2\frac{7}{12} kg of plant food did Sheldon have left.

b) She need is \frac{43}{12} kg and she don't have enough to left.

Step-by-step explanation:

Given : On Sunday, Sheldon bought 4\frac{1}{2} kg of plant food. He used 1\frac{2}{3} kg on his strawberry plants and used \frac{1}{4} kg for his tomato plants.

To find :

a) How many kilograms of plant food did Sheldon have left? Write one or more equations to show how you reached your answer.

Solution :

Sheldon bought plant food 4\frac{1}{2}=\frac{9}{2} kg.

He used strawberry plants 1\frac{2}{3}=\frac{5}{3} kg.

He used tomato plants \frac{1}{4} kg

Kilograms of plant food did Sheldon have left is given by,

L=\frac{9}{2}-(\frac{5}{3}+\frac{1}{4})

L=\frac{9}{2}-\frac{23}{12}

L=\frac{54-23}{12}

L=\frac{31}{12}

L=2\frac{7}{12}

Therefore, 2\frac{7}{12} kg of plant food did Sheldon have left.

b) Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will he need? Does he have enough left to do so?

Solution :

Sheldon wants to feed his strawberry plants 2 more times.

i.e. Strawberry plants used is 2(\frac{5}{3})=\frac{10}{3} kg.

His tomato plants one more time i.e. \frac{1}{4} kg.

Total plant she need is \frac{10}{3}+\frac{1}{4}=\frac{43}{12}

As \frac{31}{12}

No she don't have enough to left.

4 0
3 years ago
A school purchases boxes of candy bars each box contains 50 candy bars each box cost $20. how much does the school have to charg
Butoxors [25]
20/50=.4  .6x50=30 so ur answer is $0.60
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Step-by-step explanation:

Vertical shift down 4 units

8 0
4 years ago
-1/3 + 7/4. in simplest form plzz
Goryan [66]
Greatest Common Factor: 12-1/3 = -4/12, 7/4 = 21/12-4/12 + 21/12 = 17/12
Answer in simplest form: 17/12
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