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valkas [14]
2 years ago
13

Write an equivalent expression by simplifying the expression using combining like terms.

Mathematics
1 answer:
Scrat [10]2 years ago
6 0
Answer: 10x + 4y + 2

The terms with an x are considered like terms so they could be subtracted.

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X+3y=9. graph using slope and y-intercept
timama [110]
Well, in order to first determine the slope or y-intercept, you must put change the equation to this format: y=mx+b.
m=slope and b=y-intercept
I
in order to do that, you must change this equation.

x+3y=9

-x     -x
----------
3y=9-x

Then, rewrite it as: 

3y=-x+9
_______
3      3

simplify to  

y=-x/3 +9



6 0
3 years ago
Read 2 more answers
1. Kyle has a baseball game after school. He drives 6 miles due west from his home to school. After school, he drives 5 miles du
sweet-ann [11.9K]

Answer:

D. 7.8 miles.

Step-by-step explanation:

So, to solve this, you need to use the Pythagorean theorem to find the distance from the baseball field to his home. You know two of the sides of the triangle formed, 6 and 5. The Pythagorean theorem is a² + b² = c². In this case, it would be 6² + 5² = c². If you solve this, you would find that c is 7.81024967591. Just round it to the nearest tenth like instructed. This would get you 7.8 as the answer.

Extra work just in case:

6² + 5² = c²

36 + 25 = c²

61 = c²

\sqrt{61} = \sqrt{c^{2} }

7.8 ≈ c

Visual just in case:

8 0
3 years ago
The value pi/2 is a solution for the equation 2sin^2 x -sinx-1=0
nikklg [1K]

me so sorry come back laterAnswer:

Step-by-step explanation:me so sorry come back later

7 0
2 years ago
) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp
Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

<em>Let </em>\bar X<em> = sample average salary</em>

The z-score probability distribution for sample mean is given by;

                 Z = \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }  ~ N(0,1)

where, \mu = mean salary = $1.5 million

            \sigma = standard deviation = $0.9 million

             n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P(\bar X > $1.1 million)

    P(\bar X > $1.1 million) = P( \frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} } >  \frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} } ) = P(Z > -8.89) = P(Z < 8.89)

<em>Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.</em>

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0
2 years ago
Solve for the variable m. m-n=5
dolphi86 [110]

if you wanna solve for m you have get m by him self.

m-n = 5

m-n+n = 5+n

m = 5+ n

there is your answer. hope it is heplful

6 0
2 years ago
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