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STALIN [3.7K]
2 years ago
9

What is the 17th term in the arithmetic sequence -1, -101, -201, -301...

Mathematics
1 answer:
OLEGan [10]2 years ago
8 0

Answer:

I assume that the question is to prove that; a/(b + c), b/(c +a) and c/(a + b) are in an A.P

Step-by-step explanation:

It is given that a^2 , b^2 and c^2 are in an AP

So they have a common difference

b^2 - a^2 = c^2-b^2

(b - a)(b + a) = (c - b)(c + b)

(b - a) / (b + c) = (c - b) / (b + a)

Let;

(b - a) / (b + c) = (c - b) / (b + a) = K

Now for a/(b + c) , b/(c + a) and c/(a+ b)

b/(c+a) - a/(b+c)

= b(b+c) - a(a+c) / (b+c)(c+a)

= b^2 + bc - a^2 - ac / (b+c)(c+a)

= (b-a)(b+a) + c(b-a)

= (b-a)(b+a+c) / (b+c)(c+a)

= K(a+b+c) / (c+a)

c/(a+b) - b/(c+a)

= c^2 + ac - ab - b^2 /

= (c-b)(c+b) + a(c-b)

= (c - b)(a+b+c) / (a+b)(c+a)

= K(a+b+c) / (c+a)

So;

b/(c+a) - a/(b+c) = c/(a+b) - b/(c+a)

Which means that terms a/(b+c) , b/(c+a) and c/(a+b) have a a common difference

Therefore a/(b+c) , b/(c+a) and c/(a+b) are in an A.P

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Increase £80 by 15%<br>​
Juliette [100K]
The answer to your question is 92
3 0
1 year ago
What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

I = \frac{P}{4\pi d^{2}}

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km     </em>

\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

3 0
3 years ago
Lee watches TV for 2 hours per day. During that time, the TV consumes 250 watts per hour. Electricity costs (10 cents)/(1 kilowa
vladimir1956 [14]

Answer:

$1.5

Step-by-step explanation:

Lets us first calculate energy consumed by TV in 30 days.

Energy consumed by TV in one hour : 250 watts.

TV operated 2 hours a day

so energy consumer by TV in a day = 250 * 2 watts = 500 watts hour

Energy consumed by TV in 30 day = energy consumer by TV in a day * 30

         = 500*30 watts = 15,000 watt-hour

Convert total energy consumed in kilo watt hour  

we know that one kilowatt hour = 1000 watt-hour

Thus, 15,000 watt-hour = 15,000/1000 kilowatt-hour = 15 kilowatt-hour

________________________________

cost of electricity = 10 cents per   kilowatt-hour

cost of electricity for 15 kilowatt-hour = 15* cost of electricity for one  kilowatt-hour( which is 10 cents)

=>15*10 = 150 cents

As $1 = 100 cents

hence 150 cents = $150/100 = $1.5 .

Thus, it cost $1.5 to to operate for a month of 30 days.

6 0
3 years ago
Please help me I'm on a time crunch
Neporo4naja [7]

You multiple it by 20....
1:20
2:40
3:60
4:80
5:100
So it’s 80 inches by 100 inches (80x100) =800 square feet
8 0
2 years ago
Read 2 more answers
6) The population of rats doubles every 8 months. If there were 23 rats to start how many
taurus [48]

Answer:

736

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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