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Mariulka [41]
1 year ago
5

Write four equivalent fractions for 3/5.

Mathematics
2 answers:
Aloiza [94]1 year ago
3 0

\frac{6}{10}  \\  \\  \frac{9}{15}  \\  \\  \frac{12}{20}   \\ \\  \frac{15}{25}

elena-s [515]1 year ago
3 0
You can multiply a number for both the numerator and denominator.

So 3/5 is the same as
(3/5) x 2 = 6/10
(3/5) x 3 = 9/15
(3/5) x 4 = 12/20
(3/5) x 5 = 15/25

They will all equal the same. 3/5 is the most simplified answer.
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Howdoyouwrite<br> 36/50<br> as a percentage?
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Answer:

72%

Step-by-step explanation:

Divide 36 by 50 to get .72, and then convert it to a percentage

8 0
3 years ago
Multiply. Express your answer as a fraction in<br> Simplest form<br> 8.33 x V 144
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Step-by-step explanation

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What equality is shown here on the number above?​
grigory [225]

Answer:

the equality shown is : x is greater than or equal to -3.

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3 years ago
-4/4- (-8/4)<br><br> Write answer as a decimal
olga_2 [115]
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8 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
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