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Katarina [22]
3 years ago
11

What is the area of a semicircle with a diameter of 12?

Mathematics
2 answers:
sertanlavr [38]3 years ago
8 0
18 is the right answer
SOVA2 [1]3 years ago
3 0

Answer:

So, area of the semicircle = 18π mm.

Step-by-step explanation:

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a balloon at standard pressure is placed in a cool oven at 20 degrees celsius. the balloon is removed from the oven when the int
alisha [4.7K]

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Step-by-step explanation:

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8 0
3 years ago
A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical​ (ha
Neko [114]

Answer:

Volume: \frac{2}{3}\pi r^3

Ratio: \frac{2}{9}r

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

V=\frac{4}{3}\pi r^3

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

A=4 \pi r^2

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so 2\pi r^2. Moreover, we have to add the surface of the base, which is \pi r^2. So the total surface area of the hemispherical tank is

A'=2\pi r^2 + \pi r^2 = 3 \pi r^2

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r

6 0
3 years ago
Find the value of X answer in simplest form
Arlecino [84]

Answer:

14.14

Step-by-step explanation:

You can find the value of x using the trig ratio Sine = opposite/hypotenuse.

The sin 45 = 10/x. Solve for x.

x= 10/ sin45

x = 10/0.707

x = 14.14

5 0
3 years ago
Can someone help me please
Morgarella [4.7K]

Answer:

<u>The volume of this figure is approximately 418.88 centimeters squared!</u>

Step-by-step explanation:

The volume for a right circular cone is V = (π)(r^2)(h/3)

Substituting known values is as follows:

V = (π)(r^2)(h/3)

V = (π)(4^2)(25/3)

V = (π)(16)(25/3)

<u>V ≈ 418.88 cm^3</u>

5 0
3 years ago
Are the following similar? Why or why not
galben [10]

Answer:

yes

Explanation:

  • the ratios of the corresponding sides are equal: 3/2
  • the corresponding angles are equal
6 0
3 years ago
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