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77julia77 [94]
3 years ago
12

Are the following similar? Why or why not

Mathematics
2 answers:
galben [10]3 years ago
6 0

Answer:

yes

Explanation:

  • the ratios of the corresponding sides are equal: 3/2
  • the corresponding angles are equal
SVETLANKA909090 [29]3 years ago
3 0

9514 1404 393

Answer:

  (a)  Yes

Step-by-step explanation:

Two angles of one triangle have the same measures as two angles of the other triangle. The triangles are similar by the AA similarity postulate.

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Identify the vertex<br><br> y= —(x — 6)^2 + 2
alisha [4.7K]
(6,2)


Mark brainliest please

Hope this helps you
8 0
3 years ago
Who is taking in more calories if the small bags of Snickers are the exact same size: A person in a group where 5 people are sha
alukav5142 [94]

Answer:

7 people sharing 2 bags

Step-by-step explanation:

7/2<5/3

6 0
3 years ago
What is the correct factorization of 6x^2 -2x -20?<br> Please get correct!
Snezhnost [94]

→ 6x² - 2x - 20

→ 6x² + 10x - 12x - 20

→ x(6x + 10 ) - 2 (6x + 10)

→ (6x + 10) (x - 2) .

for

6x - 10 = 0

6x = 10

{x\:=\:\frac{5}{3}}\\

for x - 2

x = 2

4 0
2 years ago
Isabelle is mixing red paint with blue paint to make purple paint. She adds 3/10 of a fluid ounce of red to 11/15 of a fluid oun
Anna71 [15]
She will need 3 fluid ounces of red paint
7 0
3 years ago
What are the roots for the equation x^2-2x+37=0 in simplest a+bi form
Gnesinka [82]

\boxed{x_{1}=1+6i} \\ \\ \boxed{x_{2}=1-6i}

<h2>Explanation:</h2>

Since we need to write the roots in the simplest form:

a+bi

It is obvious that the roots are complex. To solve this, let's use the quadratic formula. For the Standard Equation:

ax^2+bx+c=0

The Quadratic Formula is:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} \\ \\ Here: \\ \\ x^2-2x+37=0 \\ \\ So: \\ a=1 \\ b=-2 \\ c=37 \\ \\ x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(37)}}{2(1)} \\ \\ x=\frac{2\pm \sqrt{4-148}}{2} \\ \\ x=\frac{2\pm \sqrt{-144}}{2} x=\frac{2\pm \sqrt{-1}\sqrt{144}}{2} \\ \\ x=\frac{2\pm 12\sqrt{-1}}{2} \\ \\ but \ \sqrt{-1}=i \\ \\ Two \ solutions: \\ \\ x_{1}=\frac{2+12i}{2} \\ \\ \boxed{x_{1}=1+6i} \\ \\ x_{2}=\frac{2-12i}{2} \\ \\ \boxed{x_{2}=1-6i}

<h2>Lean more:</h2>

Real Roots: brainly.com/question/13740312#

#LearnWithBrainly

6 0
3 years ago
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