Answer:
4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.
Explanation:
The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:
1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.
Mass of SiC = 3.00kg = 3000.00 g
1 kg = 1000 g
Molecular mass of SiC = 40 g/mol
Moles of SiC = 
According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.
Then 75 moles of SiC will be produce from:
of silicon dioxide.
mass of 75 moles of silicon dioxde:
4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.
<span>Avogadro's number
represents the number of units in one mole of any substance. This has the value
of 6.022 x 10^23 units / mole. This number can be used to convert the number of
atoms or molecules into number of moles. We do as follows:
0.24 g (1 mol / 342.3 g) (
6.022 x 10^23 molecules / 1 mol ) =4.222 x 10^20 molecules
</span>
<u>We are given:</u>
Initial Temperature = 90°c
Final Temperature = 120°c
Heat applied(ΔH) = 500 Joules
Specific heat(c) = 0.9 Joules / g°C
Mass of Aluminium(m) = ?
<u>Change in temperature:</u>
ΔT = Final temp. - Inital Temp.
ΔT = 120 - 90
ΔT = 30°c
<u>Calculating the mass:</u>
We know the formula:
ΔH = mcΔT
replacing the values:
500 = m(0.9)(30)
500 = m(27)
m = 500/27
m = 18.52 grams
Smaller, there are many human and systematic errors that can alter the amount of product that can be obtained.
Answer:
WHAT IS THE DEFINITION FOR ISOTOPES
<u><em>the same atomic number (number of protons), but different mass number of neutrons and protons.</em></u>
WHAT ARE EXAMPLES OF ISOTOPES
<em><u>carbon</u></em>
<em><u>nitrogen</u></em>
<em><u>hydrogen</u></em>
WHAT ARE NON EXAMPLES OF ISOTOPES
<u><em>tiger-striped cat</em></u>
<u><em>idk other ones sorry...</em></u>
