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san4es73 [151]
3 years ago
10

What is the chemical name of the compound K2SO4? Use the list of polyatomic ions and the periodic table to help you answer.

Chemistry
2 answers:
Inga [223]3 years ago
8 0

Answer: Option (B) is the correct answer.

Explanation:

The given compound is K_{2}SO_{4}, that is, it contains potassium (K^{+}) and sulphate (SO^{2-}_{4}) ions.

Charge on a sulphate ion is -2 and charge on two potassium ions is +2. Therefore, according to cross multiplication method it results in the formation of K_{2}SO_{4}.

Thus, we can conclude that chemical name of the compound is potassium sulfate.

Ket [755]3 years ago
6 0

potassium sulfate or A because K2 is potassium and SO4 is sulfate

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Lana71 [14]

Answer:

31 moles

Explanation:

The balanced combustion reaction of the wax, C_{31}H_{64} is shown below as:

C_{31}H_{64}+47O_2\rightarrow 31CO_2+32H_2O

As seen from the reaction,

1 mole of wax, C_{31}H_{64} on combustion produces 31 moles of carbon dioxide, CO_2

<u>Hence, moles of CO_2 when 1 mole of wax, C_{31}H_{64} is burnt = 31 moles</u>

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3 years ago
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Explanation:

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3 years ago
Which pair of elements can be used to determine the age of a fossil that is over one billion years old?
lakkis [162]

Answer:

Explanation:

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3 0
3 years ago
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7. What is the molarity of the nitrate ion that is found in a solution made by dissolving 6.25g
tekilochka [14]

Answer:

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Explanation:

To find the molarity of the nitrate ion (NO₃⁻), you need to (1) convert grams to moles (via molar mass), then (2) convert moles Al(NO₃)₃ to moles NO₃⁻, then (3) convert mL to L, and then (4) calculate the molarity. When (Al(NO₃)₃) dissolves in water, it dissociates into 3 nitrate ions. The final answer should have 3 sig figs.

(Steps 1 + 2)

Molar Mass (Al(NO₃)₃): 26.982 g/mol + 3(14.007 g/mol) + 9(15.998 g/mol)

Molar Mass (Al(NO₃)₃): 212.985 g/mol

1 Al(NO₃)₃ = 1 Al³⁺ and 3 NO₃⁻

6.25 g Al(NO₃)₃            1 mole               3 moles NO₃⁻
-------------------------  x  -----------------  x   -----------------------  =  0.0880 moles NO₃⁻
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(Steps 3 + 4)

325.0 mL / 1,000 = 0.3250 L

Molarity = moles / volume

Molarity = 0.0880 moles / 0.3250 L

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