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3 years ago

What is the value of (h o k)(2)

Mathematics

2 answers:

Helga [31]3 years ago

7 0

Answer:

-3

Step-by-step explanation:

h(k(2)) = h(k(x=2)) = h(-2) = h(x= -2)= 3/( -2+1) = 3/-1= -3

Marina86 [1]3 years ago

6 0

Answer:

-3

Step-by-step explanation:

Sorry if I'm wrong.

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Determine the value of B such that the line defined by 8x + By + 92 = 0 passes through the point (-4,12).

zvonat [6]

8x + By + 92 = 0

(-4; 12) ⇒ x = -4; y = 12

subtitute

8 · (-4) + 12B + 92 = 0
-32 + 12B + 92 = 0
12B + 60 = 0 |subtract 60 from both sides
12B = -60 |divide both sides by 12

B = -5

8 0

3 years ago

Expand and combine like terms.<br> (3c^4-5c^6)^2

lora16 [44]

Answer:

$9c^{8} -30c^{10} + 25c^{12}$

Step-by-step explanation:

We can use formula (a-b)² = a² -2ab + b².

In our example a = 3c^4 and b = 5c^6

$(3c^{4} - 5c^{6})^{2} = [3c^{4} ]^{2} - 2*3c^{4} *5c^{6} + [5c^{6}]^{2}=\\=9c^{8} -30c^{10} + 25c^{12}$

4 0

3 years ago

Find the solution of the following equation whose argument is strictly between 270^\circ270 ∘ 270, degree and 360^\circ360 ∘ 360

Natasha2012 [34]

$\rightarrow z^4=-625\\\\\rightarrow z=(-625+0i)^{\frac{1}{4}}\\\\\rightarrow x+iy=(-625+0i)^{\frac{1}{4}}\\\\ x=r \cos A\\\\y=r \sin A\\\\r \cos A=-625\\\\ r \sin A=0\\\\x^2+y^2=625^{2}\\\\r^2=625^{2}\\\\|r|=625\\\\ \tan A=\frac{0}{-625}\\\\ \tan A=0\\\\ A=\pi\\\\\rightarrow z= [625(\cos (2k \pi+pi) +i \sin (2k\pi+ \pi)]^{\frac{1}{4}}\\\\k=0,1,2,3,4,....\\\\\rightarrow z=(625)^{\frac{1}{4}}[\cos \frac{(2k \pi+pi)}{4} +i \sin \frac{(2k\pi+ \pi)}{4}]$

$\rightarrow z_{0}=(625)^{\frac{1}{4}}[\cos \frac{pi}{4} +i \sin \frac{\pi)}{4}]\\\\\rightarrow z_{1}=(625)^{\frac{1}{4}}[\cos \frac{3\pi}{4} +i \sin \frac{3\pi}{4}]\\\\ \rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]\\\\ \rightarrow z_{3}=(625)^{\frac{1}{4}}[\cos \frac{7\pi}{4} +i \sin \frac{7\pi}{4}]$

Argument of Complex number

Z=x+iy , is given by

If, x>0, y>0, Angle lies in first Quadrant.

If, x<0, y>0, Angle lies in Second Quadrant.

If, x<0, y<0, Angle lies in third Quadrant.

If, x>0, y<0, Angle lies in fourth Quadrant.

We have to find those roots among four roots whose argument is between 270° and 360°.So, that root is

$\rightarrow z_{2}=(625)^{\frac{1}{4}}[\cos \frac{5\pi}{4} +i \sin \frac{5\pi}{4}]$

5 0

3 years ago

Pls help this is due today :)

Sedaia [141]

Answer:

Left 7 down 6 Then count two spaces left right up and down and draw a circle

Step-by-step explanation:

Your answer is going to be in the bottom left corner, you count 7 vertical lines to the left, then from there you count 6 horizontal lines down. Since the Radius is 2 the diameter is 4. Good luck, if this wasn't helpful enough you can get a graphing calculator for yourself.

5 0

3 years ago

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What number is 54% of 125 type an integer or a decimal round to the nearest tenth

eimsori [14]

Answer is 67.5

To get this you must first turn 54% into a decimal.
54%---> .54
125*.54= 67.5
So 54% of 125 is 67.5 <span />

4 0

3 years ago

Read 2 more answers