10.<br> 12 is 30% of<br> ....

What is the interquartile range?<br><br> The interquartile range is ____

mestny [16]

Answer:

THE ANSWER IS THREE sorry cap lock

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Make x the subject 4x=y

Mandarinka [93]

Answer:

x=y/4

Step-by-step explanation:

Simply divide by 4 to get x by itself

3 0

3 years ago

AD is a diameter of a circle and AB is a chord. If AD=34cm, AB=30cm, the distance of AB from the centre of the circle is :

e-lub [12.9K]

Answer:

The distance is 8 cm

Step-by-step explanation:

The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...

BD² +AB² = AD²

BD² = AD² -AB² = 34² -30² = 256

BD = √256 = 16

The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.

distance from AB to the center = 16/2 = 8 . . . cm

7 0

3 years ago

In a particular game, a fair die is tossed. If the number of spots showing is either four or five, you win $1. If the number of

TiliK225 [7]

Answer:

The probability that you win at least $1 both times is 0.25 = 25%.

Step-by-step explanation:

For each game, there are only two possible outcomes. Either you win at least $1, or you do not. Games are independent. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability of winning at least $1 on a single game:

The die has 6 sides.

If it lands on 4, 5 or 6(either of the three sides), you win at least $1. So

$p = \frac{1}{2} = 0.5$

You are going to play the game twice.

This means that $n = 2$

The probability that you win at least $1 both times is

This is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.5)^{2}.(0.5)^{2} = 0.25$

The probability that you win at least $1 both times is 0.25 = 25%.

4 0

3 years ago

You need gas for your car, and just as you are approaching where you normally get gas, the radio station announces that the Chea

schepotkina [342]

Answer: Yes

Step-by-step explanation:

Given that:

Distance from present location to CheapGas = 4 miles

Price of gas at CheapGas is $0.37 cheaper

Hence, the decision to make a U-turn back to CheapGas or continue on intended destination will rely on two factors ;

1) The number of gallons of gas to purchase

2) The cost of gas required to return to cheap gas.

If a substantial amount of gas is to be purchased, may be 50, 100 or more gallons, the amount saved by making a turn back to cheapGas and purchase gas at $0.37 cheaper per gallon.

8 0

3 years ago

10. 12 is 30% of ....