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3 years ago

12

Given that the supply and demand function for the product type is Qd =

"TexFormula1" title="\sqrt{260-p}" alt="\sqrt{260-p}" align="absmiddle" class="latex-formula">,
Qs = $\sqrt{p-14}$ . consumer surplus ??.

1 answer:

lara31 [8.8K]3 years ago

7 0

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If beginning inventory at cost was $12,000.00, ending inventory at cost $10,4000.00, and the cost of goods sold $18,000.00, what

RoseWind [281]

Inventory turnover is
Cost of goods sold divided by the average merchandise inventory

First we should find the average merchandise inventory
Add the inventory on hand at the start of the year to the inventory on hand at the end of the year and divide the result by 2 to find the company's average inventory
(12,000+10,400)÷2=11,200

Now find the inventory turnover
Divide the company's cost of goods sold for the year by the average inventory to figure the company's inventory turnovers per year.
18,000÷11,200=1.61.....answer

Hope it helps

5 0

3 years ago

A biologist is recording the loss of fish in a pond. He notes the number of fish, f, in the pond on June 1. On July 1 there were

Paul [167]

A. F-52=63
F would equal to 115(add 63+52), so it would be 115-52=63 (fish left)

5 0

4 years ago

There is a jar of 25 black marbles and 50 red marbles what is the probability at least 2 are red

liraira [26]

2/3 chance you pull red on the first pull because there are 50 red to the 25 black marble

4 0

4 years ago

Read 2 more answers

Please could you explain this step by step I’m really stuck.

allochka39001 [22]

Answer:

x = -2.5
x = 2

Step-by-step explanation:

Hello!

We can remove the denominators by multiplying everything by it.

Solve:

$\frac{5}{x + 3} + \frac4{x + 2} = 2$
$5 + \frac{4(x + 3)}{x + 2} = 2(x + 3)$
$5 + \frac{4x + 12}{x + 2} = 2x + 6$
$5(x + 2) +4x + 12 = (2x + 6)(x + 2)$
$5x + 10 + 4x + 12 = 2x^2 + 6x + 4x + 12$
$9x + 22 = 2x^2 + 10x + 12$

Let's make one side equal to 0.

$0 = 2x^2 + x - 10$

Solve by factoring, and then the zero product property.

$0 = 2x^2 + x - 10\\$

Multiply 2 and -10. You get -20. Think of two number that multiply to -20, and add to 1. If we think about the standard form of a quadratic, $ax^2 + bx + c$ , think two numbers that equal "ac" and add up to "b".

$0 = 2x^2 - 4x + 5x - 10$
$0 = 2x(x - 2) + 5(x - 2)$
$0 = (2x + 5)(x - 2)$

Using the zero product property, set each factor to 0 and solve for x.

2x + 5 = 0
2x = -5
x = -5/2 = -2.5
x - 2 = 0
x = 2

The two answers are x = -2.5, and x = 2.

3 0

2 years ago

Read 2 more answers

Please help I need it

ohaa [14]

Answer:

6.300

Step-by-step explanation:

it is not 0.500 or above so you would round down to the nearest thousandth

5 0

2 years ago