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Dima020 [189]
3 years ago
5

A projectile is launched at a height of h feet above the ground at an angle of θ with the horizontal. The initial velocity is v0

feet per second, and the path of the projectile is modeled by the parametric equations
x=(v0cosθ)t and y=h+(v0sinθ)t-16t^2
Write the parametric equations to model the path of a projectile launched from ground level (h = 0) at the given values of θ and v0. Use your equations to answer the following questions.

θ=40∘ , v0=128 feet per second
Determine the maximum height
Give the time the object reaches this height (to one decimal place).
Give the approximate horizontal distance the objects is at this point (to one decimal place).
Determine the time the object will hit the ground after it is launched (to one decimal place).
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer:

Simple

Step-by-step explanation:

You Quit The Class

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A coin is flipped 18 times. Three of the times the coin landed on heads and the rest of the times tails. What is the difference
stira [4]

Answer:

the experimental probability is based on the results of the experiment which yielded heads 1 out of 6 times; in theory, the results of flipping a coin and landing on heads would be 1 out of 2

Step-by-step explanation:

3 0
2 years ago
Given circle P with arc AE=53, arc BA=68 and arc CB=72 match the following angles with their corresponding measurements
11Alexandr11 [23.1K]
From the diagram;
1. Angle 2 = ADB+BDH
                                           = arcAB/2 +90 
                                           = 34 +90 
                                           = 124°

2. Angle 4= 90°,
Reason ; the angle between a tangent and a radius is equal to 90. A tangent is a line that touches the circumference of a circle once even if prolonged.

3. Angle 5 = 90 -BDC (note the acr subtends twice the angle it subtends on the circumference to the center.
             = 90-arc BC/2
             = 90-36
              = 54°

4. Angle 6 = BFD
             = 180-ADB-FBD
             = 180-AB/2-DE/2
             But DE = 180 -121 = 59
Therefore, BFD = 180 -34-29.5
             = 116.5°

5. Angle 1 = 180- BFD (angles on a straight line add up to 180°)
              = 180- 116.5
              = 63.5°
           

6. Angle 3 = 180 -(ADB+BFD)
             = 180 -(34 +116.5)
             =  180- 150.5
             = 29.5°
similarly angle 3 = DE/2 = 59/2 = 29.5°

7. Angle 8= 90, because BD is diameter;
 angles subtended by a diameter to the circumference is always a right angle (90°)


8.Angle 7 =  BE
               but BE= AB+AE
                          = 68+ 53
                          = 121°
                 


    
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Here you go!

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