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Art [367]
3 years ago
11

A random sample of 12 families were asked how many kids they had. The data are given below. According to the US Census, families

have on average 2.4 kids per family. What is the p-value for the alternative hypothesis that the average number of kids per family is different than the US Census value
Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

0.308

Step-by-step explanation:

Given the data:

1, 1, 2, 2, 2, 3, 3, 3, 3, 4, 4, 6

The sample mean and standard deviation :

Sample mean, xbar = (1+1+2+2+2+3+3+3+3+4+4+6) / 12 = 2.833

Sample standard deviation, s = 1.40 ( calculator)

Hypothesis :

H0 : μ = 2.4

H0 : μ ≠ 2.4

The test statistic :

(xbar - μ) ÷ (s/√(n))

(2.833 - 2.40) / (1.40/sqrt(12))

Test statistic = 1.0713

Using the Pvalue from Test score calculator :

df = n - 1 = 12 - 1 = 11

Pvalue(1.071, 11) two - tailed

= 0.3069

= 0.307

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Pythagorean theory m3/9=3
Anna71 [15]

Answer:

Step-by-step explanation:

m3/9=3

We move all terms to the left:

m3/9-(3)=0

We multiply all the terms by the denominator

m3-3*9=0

We add all the numbers together, and all the variables

m^3-27=0

#learnwithbrainly

6 0
3 years ago
A display case of hat pins are marked 5 for $3. If Patty has $21, how many hat pins can Patty get? (assume no other taxes and fe
Nonamiya [84]
Answer: 35

Explanation: If patty has $21, and $3 is the price for 5 hat pins, then: 21/3=7, so she can buy 7 packages which cost $3 and contain 5 pins, and because the question asked the number of pins, we will multiply 7 • 5 and that equals 35
4 0
2 years ago
use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos^4
Firdavs [7]

The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

#SPJ4

5 0
2 years ago
Find the first of three consecutive even integers if the sum of the first and second is 15 less than 3 times the third.
lilavasa [31]

Answer:

<em>First even integer: 6</em>

Step-by-step explanation:

<u>Inequalities</u>

Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.

The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:

x+x+2

Operating:

2x+2

Subtracting 2 and 2x:

0

Simplifying:

0

Solving:

x>5

There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):

First integer: 6

Second integer: 8

Third integer: 10

There are other solutions, like 20,22,24 but the first set is 6,8,10.

4 0
3 years ago
The least common multiple of 24, 28 and 45 is:
lisabon 2012 [21]

Answer: 2520

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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