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oee [108]
3 years ago
7

How far up does the ladder reach on the building?

Mathematics
2 answers:
pychu [463]3 years ago
6 0

Step-by-step explanation:

The question missing attachment (incomplete)

But the question said how far up does the ladder reach on the building?

See the attachment

Let the tita be 60° and the height of the building be 50 meters

Now

Opposite/hypotenuse = sin(tita)

50/x = sin60°

Cross multiply to find x

x = 50/sin(60°)

x= 50/0.8660

x=57.7 meters

mariarad [96]3 years ago
5 0

Answer:

A. 6.67 m

Step-by-step explanation:

Below are attachments containing the complete question and solution

You might be interested in
What value of y makes y/4=1.3/2 a proportion
meriva

Answer:

y=2.6

Step-by-step explanation:

y/4=1.3/2

cross product

4*1.3=y*2

5.2=2y

y=5.2/2

y=2.6

7 0
3 years ago
What is the equation of a line through point (-4,5) that is perpendicular
OLEGan [10]

Answer:

set two equation of line y=ax+b and y=cx+d

when these two lines are perpendicular to each other, then a*c=(-1)

set answer is y=ax+b

we can know that a=1/6

bring in a=1/6 and(-4,5)

5=(1/6)*(-4)+b

=>5=(-2/3)=b

=>b=5 2/3

answer is y=(1/6)x+5 2/3

4 0
3 years ago
The Cinema Center consists of four theaters: Cinemas I, II, III, and IV. The admission price for one feature at the Center is $5
zzz [600]

Answer:

a) Matrix B = \left[\begin{array}{c}5\\7\\9\end{array}\right]

b) Matrix AB = \left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]

c) $12,695

Step-by-step explanation:

Matrix A = \left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right]

a) Matrix B = \left[\begin{array}{c}5\\7\\9\end{array}\right]

Gross Receipt = AB

\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right] . \left[\begin{array}{c}5\\7\\9\end{array}\right] = \left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]

c) Total revenue is the sum of receipts from 4 cinemas given in part b

Hence,

Total revenue = $2525 + $3620 + $2845 + $3705 = $12,695

3 0
3 years ago
Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w
Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so p = 0.6

The week has 5 days, so n = 5

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so P(X = 5).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0
3 years ago
I WILL GIVE BRAINLIEST PLEASE HELP!!!
luda_lava [24]

Answer:

Step-by-step explanation:

interchange x and y

y= 1/(x - 2)

x = 1 / (y - 2)      Multiply both sides by y - 2

x(y - 2) = 1          Remove the brackets

xy - 2x = 1          Add x to both sides

xy = 1 + 2x         Divide by x

y = (1 + 2x)/x

The brackets have been destroyed. The answer is as I've given it.

y = (1/x) + 2

5 0
3 years ago
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