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NNADVOKAT [17]
3 years ago
9

Solve for n. 6n+14=25

Mathematics
2 answers:
Paul [167]3 years ago
7 0

Answer: n=1.8

Step-by-step explanation:

6n+14=25

-14 on both sides

25-14=11

6n=11

divide 6 on both sides

n=1.83333..

velikii [3]3 years ago
4 0

Answer:

n=\frac{11}{6} of 1.8333...

Step-by-step explanation:

6n+14=25

-14       -14

6n=11

÷6  ÷6

<u><em>n=</em></u>\frac{11}{6}

<u>DOUBLE CHECK</u>

6(\frac{11}{6})+14=25

11+14=25

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Hey can you please help me posted picture of question
statuscvo [17]
The correct answer is the option A.

 The explanation is shown below:

 The option A is theoretical probability, because they did not make any experiment to determine the probability, while in the others options, they had to make equal tests for to determine the probability.

 For example, Lisa had to attempted 25 basketball free throws to determine which one them she could make and, then, determine the probability. While Kelli did not have to make any test.
3 0
4 years ago
PLEASE I NEED HELP WITH THIS ONE!!!
krek1111 [17]

Answer:

B

Step-by-step explanation:

Because it’s the right answer

7 0
3 years ago
A factory buys 10% of its components from suppliers B and the rest from supplier C. It is known that 6% of the components it buy
Aleks [24]

Answer:

The percentage of the components bought from supplier C that are faulty = 88%

Complete Question:

A factory buys 10% of its components from supplier A, 30% from supplier B,and the rest from supplier C. it is known that 6% of the components it buys are faulty. of the components bought from supplier A, 9% are faulty and of the components bought from supplier B, 3% are faulty.

find the percentage of the components bought from supplier C that are faulty ?

Step-by-step explanation:

Let x be the total components bought by the factory

Components supplied by A = 10% of x

Components supplied by B = 30% of x

The rest supplied by C:

Percentage supplied by C = 100-(30+10) = 100-40 = 60%

Components supplied by C = 60% of x

% of all faulty components = 6%

Amount of faulty component = 6% of x

faulty components from A= 9%

Amount of faulty component from A= 9% × (6% of x) = 0.0054x

faulty components from B= 3%

Amount of faulty component from A= 3% × (6% of x) = 0.0018x

Amount of faulty component from C = (6% of x) - (0.0054x+0.0018x)

= 0.06x - 0.0072x

= 0.0528x

Let the percentage of the components bought from supplier C that are faulty = y%

y% × 6% of x = 0.0528x

y% × 0.06x = 0.0528x

y% = 0.0528x/0.06x

y% = 0.88 = 88%

The percentage of the components bought from supplier C that are faulty = 88%

3 0
4 years ago
The optimal height h of the letters of a message printed on pavement is given by the formula <img src="https://tex.z-dn.net/?f=h
choli [55]

Answer:

The value of h is 42.956 approximately.

Step-by-step explanation:

Consider the provided formula h=\dfrac{0.00252 d^{2.27}}{e}.

Here d is the distance of the driver from the letters and e is the height of the​ driver's eye above the pavement. All of the distances are in meters.

We need to find the value of h where the value of d = 92.4 m, e = 1.7 m.

Substitute d = 92.4 m, e = 1.7 m in above formula and solve for h.

h=\dfrac{0.00252\left(92.4\right)^{2.27}}{1.7}

h\approx\dfrac{0.00252\left(28978.4648\right)}{1.7}

h\approx\dfrac{73.0257}{1.7}

h\approx42.956

Hence, the value of h is 42.956 approximately.

8 0
3 years ago
What is -2-m=5 and explain thanks
Stells [14]

Answer:

-7 is m

Step-by-step explanation:

-2 - -7 = 5

5 0
3 years ago
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