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Solnce55 [7]
3 years ago
7

Please help!what polynomial must be added to −5x^3 + 4x − 3 so that the sum is x^2 − x − 1?

Mathematics
1 answer:
lakkis [162]3 years ago
6 0
<h3><u>Solution:- </u></h3>

Let the number to be added be A

Now,

\begin{gathered}\implies\quad \sf −5x^3 + 4x − 3  + A = x^2 − x − 1 \\\end{gathered}

Transposing (−5x³+ 4x − 3 ) to other side-

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 -( −5x^3 + 4x − 3) \\\end{gathered}

Remember if there is a -ve sign before a bracket the signs of whole of the terms changes on opening bracket

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 + 5x^3 - 4x + 3\\\end{gathered}

Putting like terms together -

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 - x -4x +3 -1  \\\end{gathered}

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 -5x +2 \\\end{gathered}

\longrightarrowTherefore, 5x³+x²-5x +2 should be added to −5x³+ 4x − 3 to get x²− x − 1

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3 years ago
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8 0
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Maksim231197 [3]
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5 0
3 years ago
Two Social Security numbers (see Exercise 8.12) match zeros if a digit of one number is zero iff the corresponding digit of the
Roman55 [17]

Answer:

Proved

Step-by-step explanation:

From the given parameters, we have:

n = 9 i.e. the length of each security numbers

r = 2 i.e. 2 security numbers

Required

In 513 security numbers, 2 must have matching zeros

To do this, we make use of Pigeonhole principle.

First, we calculate the number of all security numbers not having matching zeros.

Each of the 9 digits can be selected in 2 ways.

2 ways implies that each digit is either 0 or not

So, total selection is:

Total = 2^9

Total = 512

Apply Pigeonhole principle

The principle states that: suppose there are n items in m containers, where n>m, then there is at least one container that contains more than 1 item.

This means that if there are 512 security number without matching zeros, then there is 1 (i.e. 512 + 1) with matching zeros.

512 + 1 = 513

8 0
3 years ago
I need help on 10 please explain
kumpel [21]
Lets approach this problem differently
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6 0
3 years ago
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