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Solnce55 [7]
3 years ago
7

Please help!what polynomial must be added to −5x^3 + 4x − 3 so that the sum is x^2 − x − 1?

Mathematics
1 answer:
lakkis [162]3 years ago
6 0
<h3><u>Solution:- </u></h3>

Let the number to be added be A

Now,

\begin{gathered}\implies\quad \sf −5x^3 + 4x − 3  + A = x^2 − x − 1 \\\end{gathered}

Transposing (−5x³+ 4x − 3 ) to other side-

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 -( −5x^3 + 4x − 3) \\\end{gathered}

Remember if there is a -ve sign before a bracket the signs of whole of the terms changes on opening bracket

\begin{gathered}\\\implies\quad \sf   A = x^2 − x − 1 + 5x^3 - 4x + 3\\\end{gathered}

Putting like terms together -

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 - x -4x +3 -1  \\\end{gathered}

\begin{gathered}\\\implies\quad \sf   A = 5x^3 +x^2 -5x +2 \\\end{gathered}

\longrightarrowTherefore, 5x³+x²-5x +2 should be added to −5x³+ 4x − 3 to get x²− x − 1

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Step-by-step explanation:

Given that probability of landing heads up in a toss of bent coin = 0.55

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write the equation of the line that passes through each pair of the point and slope intercept form : (3,4)(4,6)
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The equation of the line is y = 2x - 2

Step-by-step explanation:

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m = (6 - 4)/(4 -3)

m = 2/1

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y - y1 = m(x - x1)

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n is a positive integer with exactly two different divisors greater than 1, how many positive factors does n^2 have? A. 4 B. 5 C
Evgesh-ka [11]

Answer:

C. 5

Step-by-step explanation:

Remember that for any integer n, the integers 1 \text{and} n are both divisors (or factors) of n. First, we will prove that n is a square, and then we will compute the factors of the n².

In this case, the integer n has exactly two different divisors greater than 1. It's impossible that n=1, since 1 doesn't have positive factors greater than 1. Then n>1, therefore n itself is one of the required divisors. Denote by a the other divisor greater than 1, and note that to satisfy the condition on the divisors, a.

Because a divides n, there exists some integer k such that n=ak. We must have that k>1, if not, then k\leq 1, which implies that  ak=n\leq a, which contradicts the part above.

Now, k>1 and, by definition of divisibility, k divides n. Then k must be equal either to n or a, since we can't have three different divisors of this kind. If k=n then n=an and by cancellation, 1=a which is a contradiction. Therefore k=a and n=a^2.

We have that n=(a^2)^2=a^4. We can write n as n=a^3a=a^2a^2=a^4 \cdot 1. From the first equation, a divides n and a³ divides n. From the second equation, a² divides, and from the last one, 1 divides n and a⁴=n divides n. Thus n has exactly 5 positive factors.

 

4 0
4 years ago
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