Answer:
The probability that a freshman prefer cheese toppings is 0.241
Step-by-step explanation:
Probability of any event E = ![\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextrm%7BNumber%20of%20favorable%20outcomes%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20outcomes%7D%7D)
Here, let E : Event of choosing cheese toppings
So, the number of favorable outcomes = 14
Total number of outcomes = 58
So, ![P(E) = \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}](https://tex.z-dn.net/?f=P%28E%29%20%3D%20%20%5Cfrac%7B%5Ctextrm%7BNumber%20of%20students%20who%20like%20cheese%20toppings%7D%7D%7B%5Ctextrm%7BTotal%20number%20of%20students%7D%7D)
or, P(E) = ![\frac{14}{58} = 0.241379](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B58%7D%20%3D%200.241379)
So,the probability that a freshman prefer cheese toppings is 0.241379
Rounding of 0.241379 to the <u>nearest thousandth</u>, we get
Here , in 0.241379 thousandth digit is 3, and 3 < 5,
so the value of P(E) = 0.241