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kondor19780726 [428]
3 years ago
11

Ten friends scored the following marks in their end-of-year math exam:

Mathematics
1 answer:
S_A_V [24]3 years ago
6 0

Answer:

Given that  

Marks of ten friends

   23%, 37%, 45%, 49%, 56%, 63%, 63%, 70%, 72% and 82%

Mean = 56

Variance = 284.6

Standards deviation = 16.9

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3x - y = 2<br> 3x - y = 3
expeople1 [14]

Answer:

there is no answer ( I mean this system of equations can't be solved)

Step-by-step explanation:

Because the x eliminates itself there will be no point.

6 0
3 years ago
Find the axis of symmetry of the parabola below <br> A-Y=2<br> B-X=2<br> C-X=1<br> D-Y=1
victus00 [196]
The axis of symmetry is given by the line x = a (where a is equivalent to the x-value of the turning point of the parabola) and can be viewed as the line about which the parabola is symmetric; in this case, the parabola has an axis of symmetry of x = 2, thus the answer is B
8 0
3 years ago
A long distance runner starts at the beginning of a trail and runs at a rate of 6 miles per hour. Two hours later, a cyclist sta
yanalaym [24]
If the runner moves at 6 miles per hour for 2 hours before the cyclist starts, the runner has a 12 mile lead at the beginning. If the cyclist is going at 16 miles per hour, he is overtaking the runner at 10 miles per hour, because 16-6=10. Then, the amount of time it takes the cyclist to go 2 miles in 10 miles per hour is the answer. this is 1/5 of an hour, or 12 minutes.
5 0
3 years ago
Read 2 more answers
A fish tank that holds 80 gallons of water is 55% full. How many gallons are in the tank now? How many more gallons are needed t
stich3 [128]

Answer:

44 gallons of water.

Step-by-step explanation:

3 0
2 years ago
Find an equation of the plane orthogonal to the line
jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/d<em>t</em> (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩<em>t </em>) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨<em>x</em>, <em>y</em>, <em>z</em>⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨<em>x</em> - 9, <em>y</em> - 6, <em>z</em>⟩ • ⟨7, -7, -6⟩ = 0

7 (<em>x</em> - 9) - 7 (<em>y</em> - 6) - 6<em>z</em> = 0

7<em>x</em> - 63 - 7<em>y</em> + 42 - 6<em>z</em> = 0

7<em>x</em> - 7<em>y</em> - 6<em>z</em> = 21

so that

<em>a</em> = 7, <em>b</em> = -7, <em>c</em> = -6, and <em>d</em> = 21

4 0
3 years ago
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