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vova2212 [387]
3 years ago
6

John is deciding on how many lecture courses to take for his first semester. If three courses are worth 12 credits and five cour

ses are worth 20 credits, what is the rate of change of the number of credits per course?
4 credits per course

-4 credits per course

8 credits per course

-8 credits per course
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0
4 credits per course
Alika [10]3 years ago
3 0
(3,12)(5,20)
rate of change (slope) = (y2 - y1) / (x2 - x1)
slope = (20 - 12) / (5 - 3)
slope = 8/2 = 4 credits per course
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Ice cream shop is open within the month of june,july and august The shop served 100 fewer customers than they did in july They s
Julli [10]

The number of customers served in the ice cream shop in June, July and August are 125, 25 and 250 customers respectively

<h3>How to write and solve equation?</h3>

let

  • June = x
  • July = x - 100
  • August = 2x
  • Total customers = 400

Total = June + July + August

400 = x + (x- 100) + 2x

400 = x + x - 100 + 2x

400 = 4x - 100

400 + 100 = 4x

500 = 4x

x = 500/4

x = 125

So,

June = x

= 125 customers

July = x - 100

125 - 100

= 25 customers

August = 2x

= 2(125)

= 250 customers

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5 0
2 years ago
PLEASE HELP ME
MA_775_DIABLO [31]

Mean: $620, Mode: $600

Let's sort the rank stats.

First quartile: $580

Median: $610

Third quartile: $645

85th percentile: $685

OK, we're ready.  What happened to a and b?

c. $645 is the third quartile, 75th percentile.  That means 25% of the salaries are higher.

Answer: 25%

d.  $685 is the 85th percentile, 15% greater.

Answer: 15%

e.  The mean is the sum of all the salaries divided by the count.  

Mean = Sum / Count

So the sum is the count times the mean,

Sum = Count × Mean  = 100 × $620 = $62,000

Big payroll.

Answer: $62,000

4 0
3 years ago
Multiply and simplify: –3x2y2 • x4<br> –3x5y2<br><br> 9x5y2<br><br> –3x6y2<br><br> –3x5y6
Contact [7]

Answer:

Multiplying and simplifying the term -3x^2y^2 \:.\: x^4 we get \mathbf{-3x^6y^2}

Option C is correct option.

Step-by-step explanation:

We need to multiply and simplify: -3x^2y^2 \:.\: x^4

Simplifying the term:

-3x^2y^2 \:.\: x^4

While multiplying, the variables with same bases are multiplied: a^m\:.\:a^n=a^{m+n}

In the given question only x^2 and x^4 are variables with same bases, So we get:

=-3(x^{2+4})y^2\\=-3x^6y^2

So, multiplying and simplifying the term -3x^2y^2 \:.\: x^4 we get \mathbf{-3x^6y^2}

Option C is correct option.

4 0
3 years ago
The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
4 years ago
⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformati
goldenfox [79]

Answer:

Whereby circle \bigodotP can be obtained from circle \bigodotO by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP

Step-by-step explanation:

The given center of the circle \bigodotO = (-2, 7)

The radius of \bigodotO, r₁ = 5

The given center of the circle \bigodotP = (12, -1)

The radius of \bigodotP, r₂ = 12

The similarity transformation to prove that \bigodotO and \bigodotP are similar are;

a) Move circle \bigodotO 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle \bigodotO is increased by 2.4

We then obtain \bigodotO' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle \bigodotP

∴ Circle \bigodotP can be obtained from circle \bigodotO by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP.

7 0
3 years ago
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