Answer:
a) n<1 and n>5
b) 0 < n < -4
c) n > 2 and n < -2
Step-by-step explanation:
The signal is given by x[n] = 0 for n < -1 and n > 3
The problem asks us to determine the values of n for which it's guaranteed to be zero.
a) x[n-2]
We know that n -2 must be less than -1 or greater than 3.
Therefore we're going to write down our inequalities and solve for n
Therefore for n<1 and n>5 x [n-2] will be zero
b) x [n+ 3]
Similarly, n + 3 must be less than -1 or greater than 3
Therefore for n< -4 and n>0, in other words, for 0 < n < -4 x[n-2] will be zero
c)x [-n + 1]
Similarly, -n+1 must be less than -1 or greater than 3
Therefore, for n > 2 and n < -2 x[-n+1] will be zero
Vertical parabola opens down so
(y-k)^2=4P(x-h)
(h,k) is center
P is distance from directix to center and from center to focus (it is 1/2 distance between focus and directix)
-1 to -1/2 is a distance of 1/2
1/2 of 1/2=1/4
P=1/4
so move 1/4 down from -1/2
-3/4
center is (2,-3/4)
so
y+3/4=(x-2)^2
minus 3/4
y=(x-2)^2-3/4
f(x)=(x-2)^2-3/4
you made an error, either the last or first option doesn't have -(x+2)^2
Multiply by 2 on both sides: -4 + m = 4
add 4 to both sides: m=8
Answer:
The x-intercepts are at x = -2, x = -1, and x = 1.
The y-intercept is at y = -2.
Step-by-step explanation:
(a) Create a table containing a few values of x and y.
<u> x </u> <u> y </u>
-3 -8
-2 0
-1 0
0 -2
1 0
(b) Plot the points on your graph
They should look something the graph below.
The x-intercepts are at x = -2, x = -1, and x = 1.
The y-intercept is at y = -2.
Answer: She can buy a few.
Step-by-step explanation:
I can not anwer this uestion due to plagiarism
