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const2013 [10]
2 years ago
11

Sandra is making pizzas for a party. each pizza will have 8 slices. she plans on 2 slices per person. if there will be 12 people

at the party, how many pizzas should she make?
Mathematics
2 answers:
RUDIKE [14]2 years ago
6 0

Answer:

3 pizzas

Step-by-step explanation:

12 x 2 = 24

24 divided by 8 = 3

Radda [10]2 years ago
4 0
3 pizzas hope this helps i’m not good at explaining
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The problem is in the pictures, please show step by step how to do it. Thanks! :)
Rama09 [41]

Answer:

-4,-5/2

Step-by-step explanation:

2x^2+3x-20 =0

2x^2+8x-5x-20 =0

2x(x+4)-5(x+4) =0

(x+4)(2x-5) =0

Either,

x+4=0

x=-4

Or,

2x-5=0

2x=5

x=5/2

7 0
3 years ago
Read 2 more answers
Pls for the love of god someone explain how to do this to me
viva [34]
I’m not sure...but I think

x+y=5
If x =15
Then 15+y=5
Y= 10
The 2nd robot can do the task in 10min
5 0
3 years ago
How to find the x-intercepts of a parabola from the vertex, (-1,-108) and the y intercept (0,-105)?
Ulleksa [173]

Answer:

* The x-intercepts are -7 and 5

Step-by-step explanation:

* At first lets revise the standard and general forms of the

 quadratic function which represented graphically by the parabola

- f(x) = a(x - h)² + k ⇒ standard form

- Where point (h , k) is the vertex of the parabola

- f(x) = ax² + bx + c ⇒ general form

- Where a, b, c are constant

- c is the y-intercept ⇒ means x = 0

- h = -b/2a

- k = f(h)

* Lets solve the problem

- We will find the equation of the parabola

∵ The vertex is (-1 , -108)

∴ h = -1 and k = -108

∵ y-intercept = -105

- Equate the two forms

∵ ax² + bx + c = a(x - h)² + k ⇒ solve the (   )²

∴ ax² + bx + c = a(x² - 2hx + h²) + k ⇒ open the bracket

∴ ax² + bx + c = ax² - 2ahx + ah² + k ⇒ by comparing the two sides

∴ c = ah² + k

- Substitute the value of c , h , k in it

∴ -105 = a(-1)² + -108

∴ -105 = a - 108 ⇒ add 108 to the both sides

∴ 3 = a

- Lets write the equation in the standard form

∴ y = 3(x - -1)² + -108

∴ y = 3(x + 1)² - 108

* To find the x-intercepts means the parabola intersects the x-axis,

  then put y = 0

∴ 3(x + 1)² - 108 = 0 ⇒ Add 108 to the both sides

∴ 3(x + 1)² = 108 ⇒ divide the both sides by 3

∴ (x + 1)² = 36 ⇒ take square root for both sides

∴ (x + 1) = ± 6

# x + 1 = 6  OR x + 1 = -6

∵ x + 1 = 6 ⇒ subtract 1 from both sides

∴ x = 5

∵ x + 1 = -6 ⇒ subtract 1 from both sides

∴ x = -7

* The x-intercepts are -7 and 5

∴

3 0
3 years ago
Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
The terminal velocity of a person falling through air is about 100Km/hr. The acceleration due to gravity is 10ms−2. Use this inf
Aleonysh [2.5K]

The question here is how long does it take for a falling person to reach the 90% of this terminal velocity. The computation is:

The terminal velocity vt fulfills v'=0. Therefore vt=g/c, and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the differential equation shows that the time needed to reach velocity v is 

t= ln [g / (g-c*v)] / c. 

With v=.9 vt =.9 g/c,

t = ln [10] /c = 6.4 sec.

8 0
3 years ago
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