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3 years ago

This is an example of A. Reflection B. Diffraction C. Refraction

Chemistry

1 answer:

lord [1]3 years ago

5 0

Answer:

I believe it is B (if you get it wrong it's my fault)

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Automotive air bags inflate when sodium azide, NaN3, decomposes explosively to its constituent elements. How many moles of nitro

attashe74 [19]

Answer:

2.29 g of N2

Explanation:

We have to start with the chemical reaction:

$NaN_3~->~Na~+~N_2$

The next step is to balance the reaction:

$2NaN_3~->~2Na~+~3N_2$

We can continue with the mol calculation using the molar mass of

$NaN_3$ (65 g/mol), so:

$3.55~g~NaN_3\frac{1~mol~NaN_3}{65~g~NaN_3}=0.054~mol~NaN_3$

Now, with the molar ratio between $NaN_3$ and $N_2$ we can calculate the moles of $N_2$ (2:3), so:

$0.054~mol~NaN_3\frac{3~mol~N_2}{2~mol~NaN_3}=0.0819~mol~N_2$

With the molar mass of $N_2$ we can calculate the grams:

$0.0819~mol~N_2=\frac{1~mol~N_2}{28~g~N_2}=2.29~g~N_2$

I hope it helps!

5 0

3 years ago

Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a

svetoff [14.1K]

Answer:

The answer to your question is P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

= 373°K

Formula

$(P + \frac{a}{v^{2}} )(v - b) = RT$

Substitution

$(P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)$

Simplify

(P + 0.0094)(22.3829) = 30.586

Solve for P

P + 0.0094 = $\frac{30.586}{22.3829}$

P + 0.0094 = 1.366

P = 1.336 - 0.0094

P = 1.357 atm

7 0

3 years ago

Most of the X-rays are absorbed in which layer of Earth's atmosphere?

Rainbow [258]

Explanation:

most of the x-rays are absorbed in thermosphere of earth's atmosphere

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3 years ago

Calculate the quantity of energy released when 783 g of steam condenses. (show work)

Angelina_Jolie [31]

Answer:

firstark as brainliest

Explanation:

please

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2 years ago

What happens when an electrolyte, NaCl is added to hydrate ferric oxide solution

Dafna11 [192]

Answer:

hydrated ferric oxide is ferric hydoxide sol and is positively charged. When aqueous solution of NaCl is added to it,the Cl- ions neutralise the positive charge on the sol particles. In the absence of charge, brown precipitate is formes due to colloids can be coagulation of particles.Nov 11, 2020

Explanation: hope this help

4 0

3 years ago