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Y_Kistochka [10]
3 years ago
6

The relationships among which variable quantities are expressed by the ideal gas law equation?

Chemistry
2 answers:
Eva8 [605]3 years ago
8 0

<u><em>The  variable quantities are expressed by the ideal gas law equation are; </em></u>

<u><em>pressure, volume, temperature, number of moles</em></u>

<u><em /></u>

This question is simply based on defining the ideal gas law.

  • Now, A gas is considered to ideal if its particles are so far from each other in such a manner that they don't exhibit any forces of attraction between themselves. Now, in real life this is not possible but under high temperatures and pressure, we can have something close to it and that's why ideal gas laws are very important.

  • This law states that states that the pressure, temperature, number of moles and volume of a gas are related to each other by the formula;

PV = nRT

Where;

P is pressure

V is volume

n is number of moles

T is temperature

R is ideal gas constant (This is fixed and not variable)

The  variable quantities are expressed by the ideal gas law equation are;

<em>pressure, volume, temperature, number of moles</em>

Read more at; brainly.in/question/5212853

iris [78.8K]3 years ago
4 0

Answer:

I am positive it is: pressure, volume, temperature, number of moles.

Explanation:

Here is the equation for the ideal gas law: PV=nRT

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What is the volume of 1.9 moles of chlorine gas (Cl2) at 298 K and 1.3 atm?
matrenka [14]
<h2>Hello!</h2>

The answer is:

The correct option is option C.

V=36L

<h2>Why?</h2>

To calculate the volume of the gas sample, we need to use the Ideal Gas Law, this equation is used to relate the pressure, the volume, the mass and the temperature of a gas, so, we can isolate the volume from it.

The Ideal Gas Law equation is equal to:

PV=nRT

Where,

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V is the volume (in liter)

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T is the temperature of the gass (absolute temperature)

So, from the statement we know that:

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Then, substituting and calculating we have:

PV=nRT\\\\V=\frac{nRT}{P}=\frac{1.9moles*0.082057\frac{L.atm}{mol.K}*298K}{1.3atm}=35.74L

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Have a nice day!

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