Volume of a cube is length times width times height so do 125 times 37 times 68
Answer:
Suppose that you add 29.2 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.78 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound
Explanation:
The mass of nonvolatile solute added is ---- 29.2g
The mass of solvent benzene is ---- 0.250kg = 250g
The Kf value of benzene is ---- 5.12^oC/m.
Depression in the freezing point of the solution is --- 2.78^oC.
What is the molar mass of the unknown solute?
Substitute the given values in this formula to get the molar mass of unknown solvent:
Hence, the molar mass of unknown solute is --- 215g/mol.
Answer:
from,
moles,n = <u>number</u><u> </u><u>of</u><u> </u><u>particles</u><u>,</u><u> </u><u>N</u>
Avogadro constant
N = 8.27 * 6.022×10^23
N = 4.98 × 10^ 24particles.
In 8.27 moles of SiH, there are
4.98 × 10^24particles.
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