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astra-53 [7]
2 years ago
7

The value of the equilibrium constant K is a measure of how far the reaction proceeds toward the products at a given temperature

. A small value of K indicates that the reaction favors the _____, whereas a large value of K indicates that the _____ will be present in a higher proportion.
Chemistry
1 answer:
nordsb [41]2 years ago
3 0

The value of the equilibrium constant K is a measure of how far the reaction proceeds toward the products at a given temperature. A small value of K indicates that the reaction favors the <u>reactants</u>, whereas a large value of K indicates that the <u>products</u> will be present in a higher proportion.

<h3>What is Equilibrium Constant ? </h3>

The equilibrium constant of a chemical reaction usually denoted by the symbol K that express the relationship between the amount of reactants and products when a chemical reaction reaches equilibrium.

It is expressed as:

K_{c} = \frac{[C]^{c} \times [D]^{d} \times ...}{[A]^{a} \times [B]^{b} \times ...}

where,

K = Equilibrium constant

A, B = Products

C, D = Reactants

[A] = equilibrium concentration of A in moles

a = number of moles of A

Thus from the above conclusion we can say that The value of the equilibrium constant K is a measure of how far the reaction proceeds toward the products at a given temperature. A small value of K indicates that the reaction favors the <u>reactants</u>, whereas a large value of K indicates that the <u>products</u> will be present in a higher proportion.

Learn more about the Equilibrium Constant here: brainly.com/question/12858312

#SPJ4

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Density can be calculated using the following rule:
density = mass / volume
Therefore,
volume = mass / density

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6. 7. A hyperbaric chamber has a volume of 200. L. (a) How many moles of oxygen are needed to fill the chamber at room temperatu
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a) 24.7 mol

b) 790 g

Explanation:

Step 1: Given data

  • Volume of the chamber (V): 200. L
  • Room temperature (T): 23 °C
  • Pressure of the gas (P): 3.00 atm

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15

K = 23°C + 273.15 = 296 K

Step 3: Calculate the moles (n) of oxygen

We will use the ideal gas equation.

P × V = n × R × T

n = P × V/R × T

n = 3.00 atm × 200. L/(0.0821 atm.L/mol.K) × 296 K = 24.7 mol

Step 4: Calculate the mass (m) corresponding to 24.7 moles of oxygen

The molar mass (M) of oxygen ga sis 32.00 g/mol. We will calculate the mass of oxygen using the following expression.

m = n × M

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Four

Explanation:

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