Answer:
B: Y=1/2×+2 I think that's it
Answer:
The difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.
Step-by-step explanation:
The information provided is as follows:
- Kayden ran 8 km.
- Cayden ran half of distance Kayden ran.
- Isaac ran 1/5 of the distance Cayden ran.
- Jayden ran 1/6 of what Isaac ran.
So, using the given information it can be said that Cayden ran 4 km.
Then the distance Isaac ran is, .
Then the distance Jayden ran is,
Compute the difference (in km) between what Kayden ran and what Jayden ran as follows:
Thus, the difference (in km) between what Kayden ran and what Jayden ran is, 7.867 km.
M = 57+46
(Since she has 46 less then martha, you know to find how many martha has you have to add 46!)
M=103
So martha has 103 coins!
32 ways to change it up some but maybe more
Answer:
Length could be 14.05 ft and width 3.41 ft.
Step-by-step explanation:
The volume of the sand in the second box = 24 ft^3.
Let its base be x feet wide and y feet long.
Then 2(x + y) < 35.
The volume of sand = 0.5xy ft^3.
So 0.5xy = 24
xy = 48.
x = 48/y
Substituting ih the above inequality:
2(48/y + y) < 35
96/y + 2y < 35
2y^2 - 35y + 96 < 0
Solving 2y^2 - 35y + 96 = 0 gives y = 3.41, 14.09.
So the length could be 14.05 ft and the width 48/14 = 3.41 ft.