A. y=65+0.3x The slope is 0.3 and the y-intercept is 65.
Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.
To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.
For the left inverse, we have







We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.







First you try and figure what times 2 =12 which would be what?
They put the parabola in vertex form for us so we can just read off the answer.
y = a(x-p)² + q
has a vertex at (p,q)
Answer: (20.41, 2065.82)