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Furkat [3]
3 years ago
14

Where my Among Us fans at?!

Mathematics
2 answers:
marta [7]3 years ago
6 0
Right here:)))))))))))))))))
ankoles [38]3 years ago
3 0

Answer:

here

Step-by-step explanation:

i played it till 3 am once

You might be interested in
For this graph, mark the statements that are true.
lord [1]

Given:

The graph of function.

To find:

The correct statement for the domain and range of the given graph.

Solution:

Domain: The set of input values.

Range: The set of output value.

From the given graph it is clear that the graph represents a polynomial function.

The given graph of a polynomial function is defined for all real values of x. So, the domain is the set of all real numbers.

The graph of the function approaches from negative infinite to positive infinite. So, the output the given graph is set of all real numbers. It means the range is the set of all real numbers.

Therefore, the correct options are B and D.

6 0
3 years ago
Can someone help me with this asap
leonid [27]

1) 18

2)15

3) 32

4) 15

5) 28

6 0
3 years ago
Read 2 more answers
Write down an (in)equality which describes the solid ball of radius 3 centered at (7,1,−1). It should have a form like x2+y2+(z−
masya89 [10]

Answer:

(x-7)^2+(y-1)^2+(z+1)^2-9\le 0

Step-by-step explanation:

A ball is the solid inside a surface which is a sphere.

The equation of a sphere has the form:

(x-h)^2+(y-k)^2+(z-s)^2= r^2

Where (h,k,s) is the center and r is the radius.

When we plug the given center (7,1,-1) and radius 3 we get:

(x-7)^2+(y-1)^2+(z+1)^2= 3^2

Then we turn this into an inequality: Since the ball is inside the surface we must use the \le symbol.

(x-7)^2+(y-1)^2+(z+1)^2\le 9

Then we just subtract 9 from both sides to get:

(x-7)^2+(y-1)^2+(z+1)^2-9\le 0

6 0
3 years ago
What is the common ratio of the geometric sequence below?<br> -2, 4, 8, 16, -32, ...
Crazy boy [7]

Answer: No real answer

Step-by-step explanation:

4/-2 = -2

8/4 = 2

16/8 = 2

-32/16 = -2

The ratio is not equal and the sequence is not geometrical

6 0
2 years ago
Which statement explains how you could use coordinate geometry to prove that quadrilateral ABCD is a square?
pickupchik [31]
Options are not shown but…
A square has 4 equal length sides and a right angle

Or two equal length diagonals which are perpendicular

Or 4 right angled corners and two adjacent sides equal

Or perpendicular diagonals with the same midpoint

Using the last one…
Gradient of AC = (5 - 3)/(-3 - 3) = 2/-6 = -1/3
Gradient of BD = (7 - 1)/(1 - -1) = 6/2 = 3
-1/3 x 3 = -1 so AC and BD are perpendicular
Midpoint of AC = ((-3 + 3)/2 , (5 + 3)/2) = (0, 4)
Midpoint of BD = ((1 + -1)/2 , (7 + 1)/2) = (0, 4)
QED
3 0
2 years ago
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