[|] Answer [|]

[|] Explanation [|]
3x + 5 = 23
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Subtract 5 From Both Sides:
3x + 5 - 5 = 23 - 5
Simplify:
3x = 18
Divide Both Sides By 3:

Simplify:
X = 6
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- Check Your Work -
Substitute 6 For X:
3 * 6 + 5 = 23
Parenthesis
Exponents
Multiply
Divide
Add
Subtract
3 * 6 = 18
18 + 5 = 23
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The radii of the frustrum bases is 12
Step-by-step explanation:
In the figure attached below, ABC represents the cone cross-section while the BCDE represents frustum cross-section
As given in the figure radius and height of the cone are 9 and 12 respectively
Similarly, the height of the frustum is 4
Hence the height of the complete cone= 4+12= 16 (height of frustum+ height of cone)
We can see that ΔABC is similar to ΔADE
Using the similarity theorem
AC/AE=BC/DE
Substituting the values
12/16=9/DE
∴ DE= 16*9/12= 12
Hence the radii of the frustum is 12
Factor using the difference of squares.
a^2-b^2 = (a+b)(a-b)
100n^2-1
(10n+1)(10n-1)
Final answer: (10n+1)(10n-1)
100/5= 20
20 x 4 = 80
80 + 43 = 123
if my math is correct then none are correct
(prolly a typo)
Answer:
23
Step-by-step explanation: