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Sergeu [11.5K]
3 years ago
9

Write a quadratic function to model the graph. Please help!!

Mathematics
1 answer:
Katen [24]3 years ago
3 0

Answer:

80 because that you need to work on

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A fountain is made up of two semicircles and a quarter circle. Find the perimeter of the fountain. Round to the nearest hundredt
Firlakuza [10]

Answer:

Step-by-step explanation:

Ok so the formula for a circle is

A=πr2

The diameter of the semicircle is 15, so if you divide that by 2 you will get a radius of 7.5. Then, the next part of the formula is to square the radius, and to do that you need to multiply the radius by itself. You will then get an answer of 56.25. And then finally, you multiply 56.25 by pi, which is 3.14 and get 176.625. Then for the quarter circle, you have 2 side lengths of 15 feet. To find the area of the quarter circle, do pi times the radius(15), and square the answer. Then, divide the answer by 4 to get the quotient, 554.6025. 176.25 + 554.6025 is 730.8525 . That rounded to the nearest 100th is 730.85.

I really hope this helped and I'm sorry if it is incorrect.

5 0
3 years ago
10 Pts + Brainliest for the best answer
LenaWriter [7]

m∠PQR = m∠BQR + m∠PQB

We have m∠PQR = 116° and m∠BQR = 75°. Substitute:

116° = 75° + m∠PQB     <em>subtract 75° from both sides</em>

41° = m∠PQB

<h3>Answer: m∠PQB = 41°</h3>
3 0
3 years ago
A company plans to enclose three parallel rectangular areas for sorting returned goods. The three areas are within one large rec
Svetlanka [38]

Answer:

The largest total area that can be enclosed will be a square of length 272 yards.

Step-by-step explanation:

First we get the perimeter of the large rectangular enclosure.

Perimeter of a rectangle =2(l + w)

Perimeter of the large rectangular enclosure= 1088 yard

Therefore:

2(L+W)=1088

The region inside the fence is the area

Area: A = LW

We need to solve the perimeter formula for either the length or width.

2L+ 2W= 1088 yd

2W= 1088– 2L

W = \frac{1088-2L}{2}

W = 544–L

Now substitute W = 544–L into the area formula

A = LW

A = L(544 – L)

A = 544L–L²

Since A is a quadratic expression, we re-write the expression with the exponents in descending order.

A = –L²+544L

Next, we look for the value of the x coordinate

L= -\frac{b}{2a}

L= -\frac{544}{2X-1}

L=272 yards

Plugging L=272 yards into the calculation for area:

A = –L²+544L

A(272)=-272²+544(272)

=73984 square yards

Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:

W = 544 – L

= 544 – 272

= 272 yards

7 0
3 years ago
This composite figure is made up of three simpler shapes. What is the area of
Lady_Fox [76]

Answer:

B. 175 square cm

Step-by-step explanation:

Area of the figure = Area of parallelogram + Area of square + Area of triangle

Area of parallelogram  = (base x height)

                                      = (14 x 5)

                                       =  70 cm^{2}

Area of square =  (length x length)

                                      = (7 x 7)

                                      = 49 cm^{2}

Area of triangle = (\frac{1}{2} base x height)

                         = (\frac{1}{2} x 16 x 7)

                         = 56 cm^{2}

Area of the figure =  70+ 49 + 56

                        = 175

The area of the figure is 175 cm^{2}.

4 0
3 years ago
Geometry help please
Mariana [72]
The volume of a sphere is:

V=(4πr^3)/3, and you are told that r=5in so

V=(4π125)/3

V=500π/3 in^3

V≈523.60 in^3
4 0
3 years ago
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