Answer:
Step-by-step explanation:
Ok so the formula for a circle is
A=πr2
The diameter of the semicircle is 15, so if you divide that by 2 you will get a radius of 7.5. Then, the next part of the formula is to square the radius, and to do that you need to multiply the radius by itself. You will then get an answer of 56.25. And then finally, you multiply 56.25 by pi, which is 3.14 and get 176.625. Then for the quarter circle, you have 2 side lengths of 15 feet. To find the area of the quarter circle, do pi times the radius(15), and square the answer. Then, divide the answer by 4 to get the quotient, 554.6025. 176.25 + 554.6025 is 730.8525
. That rounded to the nearest 100th is 730.85.
I really hope this helped and I'm sorry if it is incorrect.
m∠PQR = m∠BQR + m∠PQB
We have m∠PQR = 116° and m∠BQR = 75°. Substitute:
116° = 75° + m∠PQB <em>subtract 75° from both sides</em>
41° = m∠PQB
<h3>Answer: m∠PQB = 41°</h3>
Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
B. 175 square cm
Step-by-step explanation:
Area of the figure = Area of parallelogram + Area of square + Area of triangle
Area of parallelogram = (base x height)
= (14 x 5)
= 70 
Area of square = (length x length)
= (7 x 7)
= 49 
Area of triangle = (
base x height)
= (
x 16 x 7)
= 56 
Area of the figure = 70+ 49 + 56
= 175
The area of the figure is 175
.
The volume of a sphere is:
V=(4πr^3)/3, and you are told that r=5in so
V=(4π125)/3
V=500π/3 in^3
V≈523.60 in^3