All categories

2 years ago

Expand 2(x-1) Expand 3(2x+3) Expand 7(x+5) Expand 5(2x-y)

Mathematics

1 answer:

Agata [3.3K]2 years ago

7 0

Those are the answers
2x-2
6x+9
7x+35
10x-5y

You might be interested in

An employee earns $28.50 after 3 hours and $237.50 after 25 hours. What is the slope? What does the slope represent?

konstantin123 [22]

Answer:

You ad $28.50 and $237.50 and ad 25 and 3 so 266.00 divide into 28.

5 0

3 years ago

12 What is the solution to this equation?

Levart [38]

Answer:

x=-5

Step-by-step explanation:

add 7 to 53 then divide -12 to itself and 60.

5 0

2 years ago

melanie michael has a salaried and exempt job. she earns $825 a week. one week she worked 46 hours. find her gross weekly earnin

valkas [14]

She earns 17.93$ per hour,

3 0

3 years ago

Simplify negative 8 over 3 divided by negative 2 over 6..

zavuch27 [327]

-9/3 / -2/6

= -9/3*6/-2

=-54/-6

7 0

3 years ago

Read 2 more answers

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$

we get:

$V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}$

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

4 0

3 years ago