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Norma-Jean [14]
2 years ago
5

Expand 2(x-1) Expand 3(2x+3) Expand 7(x+5) Expand 5(2x-y)

Mathematics
1 answer:
Agata [3.3K]2 years ago
7 0
Those are the answers
2x-2
6x+9
7x+35
10x-5y
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Which quantity is use to generate the error bars on a graph?
rodikova [14]
The error bars are used to indicate the variability of the data presented in a graph.

There are several quantities that can be used to generate error bars in the graph. These are:
standard deviation
standard error
confidence interval

Usually, one standard deviation above and below the mean is used although it is advised to indicate which variability data is used to generate the error bars in the graph since the 3 quantity given are not equal.
7 0
3 years ago
HELPPP PLSSSS!! SHOW YOUR WORK!!<br><br>THANKS
Kipish [7]
I belive it would be B. because of the fact that they are parallel which means their slope should stay the same...but their y-intersept would change
7 0
2 years ago
Rosa gets a 233 as a score out of 285. What is the grade, A, B, C, or F?
riadik2000 [5.3K]

Answer:

B

Step-by-step explanation:

233/285*100

0.81754*100

81.754%

3 0
3 years ago
Find the sum of the first 30 terms of the equation below: an=4n+1
Alex73 [517]
Let n = 30

We are actually looking for a_30.

a_30 = 4(30) + 1

a_30 = 120 + 1

a_30 = 121

6 0
3 years ago
Read 2 more answers
A professor using an open source introductory statistics book predicts that 10% of the students will purchase a hard copy of the
Likurg_2 [28]

Answer: The professor was not accurate with his hypothesis.

Null hypothesis: P1 = 12.5%, P2 = 42.5%, P3 = 45%

The alternate hypothesis: At least one proportion of the student will differ from the others.

Step-by-step explanation: To check if the professors hypothesis were inaccurate.

What percentage of student bought a hard copy of the book.

(25 ÷ 200) × 100 = 12.5%

What percentage of the student printed it from the web.

(85 ÷ 200) × 100 = 42.5%

What percentage of the students read it online.

(90 ÷ 200) × 100 = 45%

This means that the professor was not accurate with his hypothesis. Because the proportion of student in his hypothesis was not the same in the actual.

Therefore; the null hypothesis are

P1 = 12.5%, P2 = 42.5%, P3 = 45%

The alternative hypothesis will state that at least one of the proportion will be different from the others.

5 0
2 years ago
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