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3 years ago

Evaluate x divided 4 for x=48

Mathematics

1 answer:

ale4655 [162]3 years ago

5 0

Answer:

Step-by-step explanation:

x/4

Let x=48

Replace x in the expression

48/4

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A serological test is being devised to detect a hypothetical chronic disease. 500 individuals were referred to a laboratory for

andriy [413]

Answer: the predictive value positive of the test is 0.7

Step-by-step explanation:

Given that;

Predicted

Diesease No-Diesease Tt

Actual Diesease 225 75 300

No-Diesease 25 175 200

250 250 500

so finding the predictive value positive of the test,

predictive negative value = (175 / (75+175) )

= 175 / 250

= 0.7

Therefore the predictive value positive of the test is 0.7

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4 years ago

A baseball "diamond" is actually a square with side lengths of 90 feet. In a game, a runner tries to steal second base. How far

Verdich [7]

Answer:

about 127.28 feet

Step-by-step explanation:

The length of the hypotenuse of a right triangle with a base and a height of 90 feet each.

root (90)^2 + (90)^2

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2 years ago

Amy made a scale drawing of a theater. The scale she used was 1 inch : 3.5 feet. If the actual width of the stage is 84 feet, ho

zhuklara [117]

Answer:

24 inches

Step-by-step explanation:

I divided 84 by 3.5 getting 24 as my answer. So i knew that the stage is 24 inches wide on the drawing.

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3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

$\frac{dh}{dt}=-\frac{1}{2\pi}$

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4 years ago

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Nataliya [291]

Answer:

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Step-by-step explanation:

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3 years ago