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nikitadnepr [17]

3 years ago

12

Your dog ran away from home at 1:00 this afternoon. It is now 1:30. You know that he walks with an average speed of 1 m/s. Which

of the following pieces of information is most important for finding your dog?

1 answer:

vredina [299]3 years ago

3 0

Answer:

30m/s

Explanation:

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Only about 10% of the electromagnetic energy from an incandescent lightbulb is visible light. The bulb radiates most of its ener

AlekseyPX

Answer:

<em>1. 1.48 W/</em> $m^{2}$ <em></em>

<em>2. 4.93 x </em> $10^{-9} J/m^{3}$ <em></em>

<em>3. 33.3 V/m</em>

<em>4. 1.11 x </em> $10^{-7} T$ <em></em>

Explanation:

The step by step explanation to the question is contained in the attached images;

3 0

3 years ago

Read 2 more answers

A transverse wave on a string has an amplitude A. A tiny spot on the string is colored red. As one cycle of the wave passes by,

DiKsa [7]

Since it's a transverse wave, a particle on the string moves left and right as the wave passes by, but the particle doesn't travel forward or backward at all.

So the little red dot moves 'A' to the left, then 'A' back to the center, then 'A' to the right, then 'A' back to the center again.

All together, the red dot moves a total distance of <em>4A . (choice 'a')</em>

6 0

3 years ago

The coefficient of linear expansion of steel is 12 × 10-6 K-1 . What is the change in length of a 25-m steel bridge span when it

Westkost [7]

Answer:

0.012-m

Explanation:

∆L = α × Lo × (T-To)

α is the coefficient of linear expansion = 12 × 10-6 K-1

Lo = Initial length = 25-m

∆L = Change in length

(T-To) = 40 K

∆L = 12 × 10-6 × 25 × 40

∆L = 0.012-m

4 0

3 years ago

An initially stationary electron is accelerated by a uniform 640 N/C Electric Field. a) Calculate the kinetic energy of the elec

bulgar [2K]

Answer:

(a) 1.298 * 10^(-4) J

(b) 5.82 * 10^6 m/s

Explanation:

Parameters given:

Electric field, E = 640 N/C

Distance traveled by electron, r = 15 cm = 0.15 m

Mass of electron, m = 9.11 * 10^(-31) kg

Electric charge of electron, q = 1.602 * 10^(-19) C

(a) The kinetic energy of the electron in terms of Electric field is given as:

K = (q² * E² * r²) / 2m

Therefore, Kinetic energy, K, is:

K = [(1.602 * 10^(-19))² * 640² * 0.15²] / [2 * 9.11 * 10^(-31)]

K = {23651.981 * 10^(-38)} / [18.22 * 10^(-31)]

K = 1298.13 * 10^(-7) J = 1.298 * 10^(-4) J

(b) To find the final velocity of the electron, we have to first find the acceleration of the electron. This can be gotten by using the equations of force.

Force is generally given as:

F = ma

Electric force is given as:

F = qE

Therefore, equating both, we have:

ma = qE

a = (qE) / m

a = (1.602 * 10^(-19) * 640) / (9.11 * 10^(-31))

a = 112.54 * 10^(12) m/s² = 1.13 * 10^(14) m/s²

Using one of the equations of motion, we have that:

v² = u² + 2as

Since the electron started from rest, u = 0 m/s

Therefore:

v² = 2 * 1.13 * 10^(14) * 0.15

v² = 3.39 * 10^(13)

v = 5.82 * 10^6 m/s

The velocity of the electron after moving a distance of 15 cm is 5.82 * 10^6 m/s.

8 0

3 years ago

How does kinetic energy affect the stopping distance of a small vehicle compared to a large vehicle?

zhannawk [14.2K]

The equation for kinetic energy is KE=1/2mv^2
So if the small vehicle AND the large vehicle both had the same speed, the large vehicle would have more kinetic energy since it has greater mass, resulting in a much more larger stopping distance than the smaller car.

6 0

4 years ago