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sweet-ann [11.9K]
4 years ago
6

What do safety features in a car do to protect us in a collision​

Physics
1 answer:
balu736 [363]4 years ago
3 0
Make sure you don’t fly out the window
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A thin flake of mica ( n = 1.58 ) is used to cover one slit ofa double slit interference arrangement. The central point on thevi
ELEN [110]

Answer:

the thickness of the mica is 6.64μm

Explanation:

By definition we know that the phase between two light waves that are traveling on different materials (in this case also two) is given by the equation

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))

Where

L = Thickness

n = Index of refraction of each material

\lambda = Wavelength

Our values are given as

\Phi = 7(2\pi)L=tn_1 = 1.58n_2 = 1\lambda = 550nm

Replacing our values at the previous equation we have

\Phi = 2\pi(\frac{L}{\lambda}(n_1-n_2))7(2\pi) = 2\pi(\frac{t}{\lambda}(1.58-1))

t = \frac{7*550}{1.58-1}\\t = 6637.931nm \approx 6.64\mu m

the thickness of the mica is 6.64μm

5 0
3 years ago
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
n200080 [17]

Answer:

a) 4.9 s

b) 167.8 m

Explanation:

Hello!

To solve this question we need to make use of the equations of motion of both the motorcycle xm(t) and the car xc(t) at t=5

Let us consider the position of the motorcycle at t=5 as the origin, that is:

xm(t+5) = vt + (1/2)at^2

xc(t+5) = vt + 60 m

where v = 22.0m/s  and   a=5m/s^2

We are looking for the time t' when the position of the car and the motorcycle are the same:

xm(t'+5)=xc(t'+5)

vt' + (1/2)at'^2 = vt' +60m

t' = √(120 m /a) = 4.89898... s

Since we are considering the origin of the cooordinate system at the position when the motorcycle starts to accelerate, the distance travelled by the motorcycle until it catches the car is given by:

xm(t'+5)= vt' + (1/2)at'^2

xm(9.89898s) = (22 * 9.89898 + 2.5 * 9.89898^2)m

xm(9.89898s)= 167.777... m

3 0
3 years ago
A combination of two or more simple machines is a (n)
Lilit [14]
A compound Machine is 2 machines that work together in order to make a task easier.
8 0
3 years ago
How would i solve these problems, nobody in my class understands and there is a substitute
DiKsa [7]

1) X-component: 568.5 N, Y-component: 511.9 N

2) The horizontal force is 86.6 N and the resulting acceleration is 0.87 m/s^2

Explanation:

1)

In this first part of the problem, we have to resolve the force into its two components, along the x and the y direction.

The two components are given by:

F_x = F cos \theta\\F_y = F sin \theta

where

F = 765 N is the magnitude of the force

\theta=42.0^{\circ} is the angle of the force with the horizontal

Substituting, we find:

  • Horizontal component: F_x = (765)(cos 42.0^{\circ})=568.5 N
  • Vertical component: F_y = (765)(sin 42.0^{\circ})=511.9 N

2)

First of all, we have to find the horizontal component of the pulling force, which is given by

F_x = F cos \theta

where

F = 100 N is the magnitude of the pulling force

\theta=30.0^{\circ} is the direction of the force with the horizontal

Substituting,

F_x = (100)(cos 30^{\circ})=86.6 N

Now we can find the acceleration of the wagon by using Newton's second law:

F_x = ma_x

where

F_x = 86.6 N is the net force in the horizontal direction

m = 100 kg is the mass of the wagon

a_x is the acceleration in the horizontal direction

Solving for a_x, we find

a_x = \frac{F_x}{m}=\frac{86.6}{100}=0.87 m/s^2

Learn more about vector components:

brainly.com/question/2678571

And about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

5 0
3 years ago
What is the kinetic energy of an object with a mass of 10 kilograms traveling at a speed of 10 meters per second?
bagirrra123 [75]

Answer:

500 J

Explanation:

Kinetic Energy = (mass x velocity x velocity) ÷ 2

We know that mass = 10 kg and velocity = 10 m/s.

KE = (m × v × v) ÷ 2

KE = (10 kg × 10 m/s × 10 m/s) ÷ 2

KE = 500 J

The kinetic energy of the object is 500 J (joules). Hope this helps, thank you !!

5 0
3 years ago
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